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juin [17]
2 years ago
14

Darryl deposits $1,500 into a savings account that has a simple interest rate of 2.7%. Lori deposits $1,400 into a savings accou

nt that has a simple interest rate of 3.8%. If no other transactions are made, who will have more money in their account after 10 years? How much more?
Mathematics
2 answers:
elixir [45]2 years ago
6 0

Answer:

Lori will make $27.00 more.

Step-by-step explanation:

The formula to calculate simple interest is

A = P(1+rt)

P = Principal amount

r = rate of interest ( in decimal )

t = time

First we calculate Darryl's deposit, so put the values in the formula

A = 1,500(1 + 0.027×10)

A = 1,500 ( 1+0.27 )

A = 1,500 × 1.27

A = $1905

Now we will calculate Lori's deposit

A = 1,400 ( 1 + 0.038 × 10 )

A = 1,400 ( 1 + 0.38 )

A = 1,400 × 1.38

A = $1,932

Lori will make money after 10 years = $1,932

Darryl will make money after 10 years = $1905

so Lori will make more than Darryl, the difference will be = 1,932 - 1,905 = $27

After 10 years Lori will have make $27.00 more in their account.

igor_vitrenko [27]2 years ago
3 0
Darryl:
Answer:
A = $1,905.00

(I = A - P = $405.00)

Equation:
A = P(1 + rt)

Lori:

Answer:
A = $1,932.00

(I = A - P = $532.00)

Equation:
A = P(1 + rt)

Thus $532-$405= $127 more in Lori's account
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ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
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The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


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Answer:

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Step-by-step explanation:

Algebraic Expression:

An algebraic expression is a mathematical expression that consists of variables, numbers and operations.

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