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2 years ago

According to the number line, what is the distance between points A and B?

Mathematics

1 answer:

Ainat [17]2 years ago

3 0

Answer:

D)14 units

Step-by-step explanation:

Just counts how many numbers you get from point A to B. Its pretty simple.

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The speed limit on a road is 60 mph. The actual speeds of cars are measured and found to be normally distributed with a mean val

Vladimir79 [104]

Answer: 8.1%

Step-by-step explanation:

Given : $\mu=63$

$\sigma=5$

Let x be the random variable that represents the actual speeds of cars.

The speed limit on a road is 60 mph.

Using formula , $z=\dfrac{x-\mu}{\sigma}$ , we have for x= 60+10=70

$\dfrac{70-63}{5}=1.4$

Using z-table for right-tailed test value, The probability of cars exceed the speed limit by more than 10 mph will be

$P(x>70)=P(z>1.4)=0.0807567\approx0.081=8.1\%$

Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.

6 0

2 years ago

Lori recently quit her job and decided to start her own company, which will sell makeup to small beauty salons. What should she

skad [1K]

She should "Decide how to price her product". Which is response B.

This is because all the other options don't really make sense. You can't advertise something that you don't even know how much it costs. We've also already decided what the company sells. And we can't decide where the product will be sold unless we have made up the price for the product!

Hope this helps!

3 0

2 years ago

in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

NORMSINV(0.95) and we get a value of 1.645

The 90% confidence interval for the proportion is then

$\bf [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]$

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0

2 years ago

If 9 = c, then c = 9. What algebraic equality property justifies the above statement?

netineya [11]

Symmetric property is the correct term

4 0

2 years ago

Assume 6 in every 2000 students at the local community college have to quit due to serious health issues. An insurance company o

Alexus [3.1K]

Given:

6 out of 2000 students quit community college due to serious health issues.
$10,000 insurance company offer
$60 per year

Based on the data, there are 6 students who will be given the $10,000 insurance per year. So they need

6 * 10,000 = $60,000 to make a break-even on their insurance offer

If a student pays $60 per year, they should have

$60,000 / $60 = 1,000 students who will pay per year to reach the break-even mark of their investment. If the number of students will exceed 1,000, the company will begin to earn.

7 0

2 years ago