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givi [52]
2 years ago
12

A sociologist studying the difference in ages between husbands and wives obtained a random sample of 55 married couples. The mea

n of the husbands’ ages was 38.5 years with standard deviation 12.6 years. The mean of the wives’ ages was 36.9 years with standard deviation 12.4 years. The sociologist calculated the difference between the ages for each couple. The mean difference was 1.6 years with standard deviation 2.1 years. A matched-pairs hypothesis test will be performed to investigate whether the difference is significant.
Mathematics
1 answer:
zalisa [80]2 years ago
8 0

Answer:

2.1/√55

Step-by-step explanation:

simga divided by sample size

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eight out of 10 dentist prefer Crest toothpaste.What is the ratio of dentist whi prefer Crest to those who do
crimeas [40]
The ratio would be 8:2
6 0
2 years ago
A salesman used three types of order forms: A, B, C. He used 40 of Form A. Of Form B he used four times as many as Form A plus 1
aivan3 [116]

Answer:

a. 440

Step-by-step explanation:

The information provided allows us to set up the following system of linear equations:

A = 40\\B=4A+0.5C\\C=A+0.5B

We already have the value for A, solving the system gives us the values for B and C:

A = 40\\B=(4*40)+0.5C\\C=40+0.5B\\\\B -B-80 = (4*40)+0.5C-2C\\C=\frac{160+80}{1.5}\\C=160\\B= (4*40) +(0.5*160)\\B=240

The total number of forms used is:

A+B+C = 40+240+160 = 440

He used 440 forms.

4 0
2 years ago
Read 2 more answers
Compare the decimals by using the symbol < or >. a. 0.531 _____ 0.456 b. 0.63 _____ 0.47 c. 0.267 _____ 0.539 d. 0.07 ____
rodikova [14]

Answer:

0.531  > 0.456

0.63 > 0.47

0.267  < 0.539

0.07 < 0.7

Step-by-step explanation:

a. 0.531 _____ 0.456

compare the numbers from left to right

5 is greater than 4 so 0.531 greater than 0.456

0.531  > 0.456

b. 0.63 _____ 0.47

6 is greater than 4. 0.63 > 0.47

c. 0.267 _____ 0.539

2 is less than 5 . so 0.267 less than 0.539

0.267  < 0.539

d. 0.07 _____ 0.7

0 is less than 7

0.07 < 0.7

6 0
2 years ago
On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p
notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}

Now,

Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

7 0
2 years ago
In a survey of 2,300 people who owned a certain type of car, 1,610 said they would buy that type of car again. What percent of t
trapecia [35]

Answer:

In a survey of 2,300 people who owned a certain type of car, 1,610 said they would buy that type of car again. What percent of the people surveyed were satisfied with the car?

1610/2300x100=

70%

Step-by-step explanation:

total number of people for the survey= 2300

those that wanted to buy the car= 1610

percentage= 1610/2300x 100=0.7x 100

percentage= 70%

3 0
2 years ago
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