Answer:
A)Percentile for Lynette, the student who is 65 in. tall is 36th
B) Asher is 22 inches tall.
Step-by-step explanation:
Percentile : It is a measure used in statistics indicating the value below which a given percentage of observations in a group of observations falls
A) Find the Percentile for Lynette, the student who is 65 in. tall.
No. of students below 65 inch =9
So, Percentage of data below 65 inch =
So, Percentile for Lynette, the student who is 65 in. tall is 36th
B)Ashers height is at the 88th percentile of the distribution. Interpret this value in context. How tall is Asher
22=x
So, No. of students below or st 88th percentile = 22
So, Asher is 22 inches tall.
Positive 14/472 (because of rise over run when finding slope)
Hello there!
the answer is 8.33
Hope I helped!
Let me know if you need anything else!
~ Zoe
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Answer:
The answer is below
Step-by-step explanation:
The volume of a cuboid is the product of its length, height and breadth. It is given by:
Volume = length × breadth × height
Since the volume is given by the expression 12y² + 8y - 20. That is:
Volume = 12y² + 8y - 20 = 4(3y² + 2y - 5) = 4(3y² + 5y - 3y -5) = 4[y(3y + 5) -1(3y + 5)]
Volume = 4(y-1)(3y+5)
Or
Volume = 12y² + 8y - 20 = 2(6y² +4y - 10) = 2(6y² + 10y - 6y -10) = 2[y(6y + 10) -1(6y + 10)]
Volume = 2(y-1)(6y+10)
Therefore the dimensions of the cuboid are either 4, y-1 and 3y+5 or 2, y-1 and 6y+10
