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Strike441 [17]
2 years ago
6

At a carnival, single rides cost $2 each, and all day ride passes cost $15. The total revenue for the day was $2,960. Which equa

tion can be used to represent x, the number of single ride passes sold and y, the number of all day ride passes sold?
Mathematics
2 answers:
Vaselesa [24]2 years ago
7 0

Answer:

2x+15y=2,960 is the correct answer.

Step-by-step explanation:

Hope this helps the equation is 2x+15y=2,960 and Since you didn't ask for answer there is no explanation :)

mixas84 [53]2 years ago
5 0
2x+15y=2,960 would be the equation
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I’m just going off of what I was told in fifth grade, and we were told it was finger nails. Hope this helps!
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In a chemical compound there are three parts zinc for every 16 parts copper by mass. A piece of the compound contains 320 g of c
Orlov [11]
<span>Total mass contains 320g copper. How many parts of 16g copper are there of the total mass of 320g copper? 320/16 = 20. There are 20 portions of 16g copper. (320/16) * 3 = 60g There are 60g of zinc in the compound.</span>
6 0
2 years ago
Ecologists sometimes find rather strange relationships in our environment. For example, do beavers benefit beetles? Researchers
Harman [31]

Answer:

The appropriate conclusion that answers the question stated in step one is:

  • The weak correlation value does not support the idea that beavers benefit beetles.
  • The largest number of beetle larvae was 55 and the largest number of stumps was 5.

Step-by-step explanation:

1) Select the appropriate practical question.

The appropriate practical question is:

"How does the number of beaver-caused stumps influences the number of beetle larvae clusters?"

2) Make a scatter plot.

The scatter plot is attached below.

From the scatter plot it can be seen that there exists a negative relationship between beaver stumps and beetle larvae. That is as the number of stumps increases the number of beetle larvae decreases.

The maximum number of beaver stumps found is 5.

3)

The best numerical summary for this problem are,

Correlation and regression line

The least square regression line for predicting the number of beetle larvae from the number of stumps is:

<em>y</em> = 31.594 - 2.8365 <em>x</em>.

Use the Excel function "=CORREL(array1,array2)" to compute the correlation.

The correlation value is, <em>r</em> = -0.219.

Both the correlation coefficient and regression line explains a negative relationship between the number of beetle larvae and the number of stumps.

Values amid 0 and 0.3 (0 and -0.3) implies a weak positive (negative) linear relationship amid the variables.

Thus, a correlation coefficient, r = -0.219, indicates a weak negative correlation between two variables.

Thus, the appropriate conclusion that answers the question stated in step one is:

  • The weak correlation value does not support the idea that beavers benefit beetles.
  • The largest number of beetle larvae was 55 and the largest number of stumps was 5.

3 0
2 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
2 years ago
Can someone help meee???
Phoenix [80]

Answer:

Step-by-step explanation:

Couldn't really read the tables so i'd double check to make sure i'm correct

4 0
2 years ago
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