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mixer [17]
2 years ago
12

Tumor counts: A cancer laboratory is estimating the rate of tumorigenesis in two strains of mice, A and B. They have tumor count

data for 10 mice in strain A and 13 mice in strain B. Type A mice have been well studied, and information from other laboratories suggests that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12. Tumor count rates for type B mice are unknown, but type B mice are related to type A mice. The observed tumor counts for the two populations are
Mathematics
1 answer:
Igoryamba2 years ago
3 0

Answer:

The observed tumor counts for the two populations of mice are:

Type A mice = 10 * 12 = 120 counts

Type B mice = 13 * 12 = 156 counts

Step-by-step explanation:

Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.

This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate).  And the Poisson distribution gives the probability of an occurrence within a specified time interval.

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What is the cube root of -729a9b6
Harman [31]

<u>ANSWER</u>

\sqrt[3]{- 729{a}^{9}  {b}^{6} }  =  - 9 {a}^{3} {b}^{2}

<u>EXPLANATION</u>

We want to find the cube root of

- 729 {a}^{9}  {b}^{6}

We express this symbolically as:

\sqrt[3]{- 729 {a}^{9}  {b}^{6} }

The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

{x}^{ \frac{m}{n} }  =  \sqrt[n]{ {x}^{m} }

Applying this rule gives us:

\sqrt[3]{- 729 {a}^{9}  {b}^{6} }  =  ({- 729 {a}^{9}  {b}^{6}})^{ \frac{1}{3} }

\sqrt[3]{- 729{a}^{9}  {b}^{6} }  =  ({- {9}^{3}  {a}^{9}  {b}^{6}})^{ \frac{1}{3} }

Recall that

({a}^{m} )^{n} = {a}^{mn}

We apply this rule on the RHS to get,

\sqrt[3]{- 729{a}^{9}  {b}^{6} }  =  ({- {9}^{3 \times { \frac{1}{3} } }  {a}^{9 \times { \frac{1}{3} } }  {b}^{6 \times { \frac{1}{3} } }})

This simplifies to

\sqrt[3]{- 729{a}^{9}  {b}^{6} }  =  - 9 {a}^{3} {b}^{2}

3 0
2 years ago
Read 2 more answers
Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un
Nataly_w [17]

Answer: 0.1289

Step-by-step explanation:

Given : The proportion of all students at a large university are absent on Mondays. : p=0.15

Sample size : n=12

Mean : \mu=np=12\times0.15=1.8

Standard deviation = \sigma=\sqrt{np(1-p)}

\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369

Let x be a binomial variable.

Using the standard normal distribution table ,

P(x=4)=P(x\leq4)-P(x\leq3)              (1)

Z score fro normal distribution:-

z=\dfrac{x-\mu}{\sigma}

For x=4

z=\dfrac{4-1.8}{1.2369}\approx1.78

For x=3

z=\dfrac{3-1.8}{1.2369}\approx0.97

Then , from (1)

P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289    

Hence, the probability that four students are absent = 0.1289

3 0
2 years ago
a television station found that 145 out of the 350 people surveyed watched a program on education on Monday night. if this surve
Oliga [24]
About 4,934 people.

12,250 × 145
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= 4,934.02777...
6 0
2 years ago
1. Your furniture store sells two types of dining room tables. The first, type A, costs $265 and you make a $25 profit on each o
Gnom [1K]
Let x represent the number of type A table and y represent the number of type B tables.
Minimize: C = 265x + 100y
Subject to: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1

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For (39, 1): C = 265(39) + 100 = $10,435
For (30, 1): C = 265(30) + 100 = $8,050

Therefore, for minimum cost, 20 of type A and 20 of type B should be ordered.
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2 years ago
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Which lines are parallel if M^4 +M^5? Justify your answer.
Igoryamba
Opposite angles formed by two intersecting lines are equal, so angle 1 is the same as angle 4. That means angle 1 = angle 5 as well. 

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