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mr_godi [17]
1 year ago
9

Annual income of A is 10% more than of B whereas income of B is 20% more than that of C. If monthly income of C is $ 2000 then w

hat is the sum of monthly incomes of A, B and C? 
A. $ 6,872
 B. $ 7,046
 C. $ 7,772
 D. $ 7,040​
Mathematics
1 answer:
Vanyuwa [196]1 year ago
3 0

Answer:

7040

Step-by-step explanation:

C= 2000

B = 20/100 x 2000 = 400 + 2000 = 2400

A= 10/100 x 2400 = 240+2400= 2640

2000 + 2400 + 2640 = 7040

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For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
3 0
2 years ago
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Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths y (in inches) in differe
Effectus [21]
<span>Given the table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.

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    3                     4                              7
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To solve for the cousins hair, recall that the equation of a line is given by

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7 = 3m + c . . . (1)
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(1) - (2) ⇒ -2 = -5m
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Substituting for m into equation (1) gives:

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Therefore, the equation representing the growth of the cousin's hair is given by y = 1.2x + 5.8
</span>
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2 years ago
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2 years ago
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