Answer:
4, 5, 27.
Step-by-step explanation:
Let us find our numbers using given information.
Factors of 20 are: 1,2,4,5,10 and 20.
Let us try by taking number 4 and 5.
We can see that 
Now let us find sum of these numbers.

Therefore, numbers chosen by Boris will be 4, 5 and 27 as these numbers satisfies our all conditions.
Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Answer:
For First Solution: 
is the solution of equation y''-y=0.
For 2nd Solution:
is the solution of equation y''-y=0.
Step-by-step explanation:
For First Solution: 
In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

First order derivative:

2nd order Derivative:

Put Them in equation y''-y=0
e^t-e^t=0
0=0
Hence
is the solution of equation y''-y=0.
For 2nd Solution:

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

First order derivative:

2nd order Derivative:

Put Them in equation y''-y=0
cosht-cosht=0
0=0
Hence
is the solution of equation y''-y=0.
Answer:
48 cm
Step-by-step explanation:
Given:
Distance of rod from the wall = 45 cm
Distance of rod from the light = 15 cm
Length of rod = 12 cm
We can see that <DAM and <BAF are equal
Also, <DMA and <BFM are equal because they are corresponding angles
To find the length of the shadow, let's take the equation

Where.:
DM = ½ of length of the rod = ½*12 = 6
A.F = 15 + 45 = 60 cm
AM = 15 cm
Therefore,


Cross multiplying, we have:
15 * B.F = 60 * 6
15 * B.F = 360

BF = 24 cm
The shadow on the wall =
2 * BF
= 2 * 24
= 48 cm
The shadow on the wall is 48 cm
For this question you would have to expand the numbers to the thounsandths
so it can be 9.181, 9.182, 9.183 and so on