Answer : Remaining two observation becomes 97 and 107.
Explanation :
Since we have given that
Mean = 100
Modal value = 98
Range = 10
As we know that ,
Range = Highest-Lowest
Let highest observation be x
Let lowest observation be y
So equation becomes x-y=10 ----equation 1
So, observation becomes
x,98,98,y
Now, we use the formula of mean i.e.
Mean = 
So, mean =
So our 2nd equation becomes
x+y=204
On using elimination method of system of linear equation on these two equation we get,
x=97
and
Hence , remaining two observation becomes 97 and 107.
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Answer:
4.43
Step-by-step explanation:
7.90
- 3.47
__________
4. 4 3
I couldn't regroup but of you cross out 0 and put 10, 10-7= 3
and you have to borrow one from 9 and make it 8 and 8-4=4
The gardener will need to buy 60 feet of fencing. Because the square root of 225 if 15, and 15 times 4 is 60. So, 60 is the perimeter of the garden.
Answer:
E(X) = 1.28
Var(X) = 0.6016
E(X | Y=2) = 1.6667
Var(X | Y=2) = 0.4272
Step-by-step explanation:
