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2 years ago

Morgan is 15 years younger than Mrs.Santos their combined age is 44

Mathematics

2 answers:

kobusy [5.1K]2 years ago

4 0

Mr. Santos is 29

44 - 15 = 29

MariettaO [177]2 years ago

3 0

Mrs. Santos is 29, 44-15=29

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Lerok [7]

Answer:

$332in^2$

Step-by-step explanation:

The area of a regular polygon is calculated using the formula;

$Area=\frac{1}{2}ap$

where $a$ is the apothem and p is the perimeter.

It was given that, the apothem is, $a=10in.$ and the perimeter is $p=66.3 in.$

We substitute into the formula to obtain;

$Area=\frac{1}{2}\times10\times66.3in^2$

$Area=331.5in^2$

To the nearest square inch, we have;

$Area=332in^2$

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Step-by-step explanation:

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2 years ago

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kodGreya [7K]

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Where:PR = Percent Rate
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VPast = Past or Present ValueThe annual percentage growth rate is simply the percent growth divided by N, the number of years.
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2 years ago

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dimaraw [331]

Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

Step-by-step explanation:

We are given that a simple random sample of 40 current hit songs results in a mean length of 252.5 seconds.

Assume that the standard deviation of song lengths is 54.5 sec.

Let $\mu$ = population mean length of the songs

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 210 seconds {means that the sample is from a population of songs with a mean smaller than or equal to 210 seconds}

Alternate Hypothesis, $H_A$ : $\mu$ > 210 seconds {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is One-sample z-test statistics because we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean length of songs = 252.5 seconds

$\sigma$ = population standard deviation = 54.5 seconds

n = sample of current hit songs = 40

So, the test statistics = $\frac{252.5-210}{\frac{54.5}{\sqrt{40} } }$

= 4.932

The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

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2 years ago