This item can be answered through the concept of fundamental principles of counting. In the first of the four digits, there are 10 possible digits. The same with all the other 3 places or digits of the code. That is,
n = 10 x 10 x 10 x 10
Giving us the answer of 10,000. Thus, there are 10,000 possible keys for the keyless entry.
X-3y=6
x+y=2
this is an substitution problem
so first you can do is rewrite the problem by subjection one variable
x=3y+6
then substitute this in the other proble
x+y=2
(3y+6)+y=2
4y+6=2
4y=2-6
4y=-4
y=-1
then substitute the no. in the original equation.
x=3y+6
x=3(-1)+6
x=-3+6
x=3
now you got the intercepts and you draw the line and check.
it's in the IV quadrant
Answer:
probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.
Step-by-step explanation:
"Find the probability that a student chosen at random from those who play a sport does not watch rugby."
90-15= 75 students either play a sport OR watch rugby
65+71-75=
136-75=
61 people play a sport AND watches rugby
14 people play a sport and DOES NOT watch rugby
is the probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.
Answer:
Any number in form of x.y = x (1) + 1/10 (y)
where x = 5 & y > 3 , or x > 5
Step-by-step explanation:
Expanded form of 5.3 = 5 (1) + 3 (1/10)
Some decimals written in expanded form that are greater than 5.3 :
5 (1) + 4 (1/10) = 5.4
6 (1) + 2 (1/10) = 6.2
1:104 because there are 52 cards in a deck and he already drew a king, so double the chances and get 1:104?
