All categories

1 year ago

$16.46 is what percent of $634.40?

Mathematics

2 answers:

noname [10]1 year ago

8 0

The required value is 104.42

<u>Solution:</u>

Although the percentage formula can be written in different forms, it is essentially an algebraic equation involving three values,

$\mathrm{P} \times \mathrm{V}_{1}=\mathrm{V}_{2}$

where P is the percentage, $V_1$ is the first value that the percentage will modify, and $V_2$ is the result of the percentage operating on $V_1$ .

Here $P = 16.46 \text{ and } V_1 = 634.40$

On substituting the values in the formula,

$\Rightarrow 16.46\%\times634.40 \rightarrow \frac{16.46}{100}\times{634.40}$

$\frac{16.46}{100}\times634.40=\frac{10442.224}{100} \approx 104.42$

tia_tia [17]1 year ago

3 0

Answer:

104.42224

Step-by-step explanation:

16.46% of 634.40 = 0.1646 × 634.40 = 104.42224

You might be interested in

A researcher wishes her patients to try a new medicine for depression. How many different ways can she select 5 patients from 50

Readme [11.4K]

Answer:

she can select 10 different ways

7 0

1 year ago

Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea

asambeis [7]

Answer:

$n\geq 23$

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

$n\geq (\frac{z\sigma}{ME})^2$

Where:

$\sigma$ is the standard deviation
$ME$ is the desired margin of error.

We substitute our given values to calculate the sample size:

$n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23$

Hence, the smallest desired sample size is 23

3 0

1 year ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$