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Zanzabum
2 years ago
10

$16.46 is what percent of $634.40?

Mathematics
2 answers:
noname [10]2 years ago
8 0

The required value is 104.42

<u>Solution:</u>

Although the percentage formula can be written in different forms, it is essentially an algebraic equation involving three values,

\mathrm{P} \times \mathrm{V}_{1}=\mathrm{V}_{2}

where P is the percentage, V_1 is the first value that the percentage will modify, and V_2 is the result of the percentage operating on V_1.

Here P = 16.46 \text{ and } V_1 = 634.40

On substituting the values in the formula,

\Rightarrow 16.46\%\times634.40 \rightarrow \frac{16.46}{100}\times{634.40}

\frac{16.46}{100}\times634.40=\frac{10442.224}{100} \approx 104.42

tia_tia [17]2 years ago
3 0

Answer:

104.42224

Step-by-step explanation:

16.46% of 634.40 = 0.1646 × 634.40 = 104.42224

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Nadusha1986 [10]

Answer:

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}  where a\geqslant 0"

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Step-by-step explanation:

Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, "

It can be written as \sqrt{54a^7b^3} where a\geqslant 0

The given expression is \sqrt{54a^7b^3} where a\geqslant 0

To find Sadie's error and explain the correct answer :

Sadie's steps are

\sqrt{54a^7b^3}  where a\geqslant 0

=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}

=3ab\sqrt{6a^5b}

<h3>\sqrt{54a^7b^3}=3ab\sqrt{6a^5b} where a\geqslant 0</h3><h3><u>Now corrected steps are</u></h3>

\sqrt{54a^7b^3}  where a≥0

=\sqrt{(9\times 6)(a^{6+1})(b^{2+1})

=\sqrt{(3^2\times 6)(a^6.a^1)(b^2.b^1) (by using the identity a^{m+n}=a^m.a^n

=\sqrt{3^2\times 6\times ((a^3)^2.a)(b^2.b) (by using the identity a^{mn}=(a^m)^n )

=3ab\sqrt{6ab}

Therefore \sqrt{54a^7b^3}=3ab\sqrt{6ab}  where a\geqslant 0

<h3>The correct answer is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b} " where a\geqslant 0

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>
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For this case we have the following expression:

7a-2b = 5ab

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