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1 year ago

9

Find the general solution of the given second-order differential equation. 25y'' − 15y' − 4y = 0

1 answer:

SashulF [63]1 year ago

8 0

Consider, pls, this option.

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A lamp shade has a radius of 9 inches. What is the circumference of the top of the shade? Use 3.14 to approximate pi. Round your

Angelina_Jolie [31]

Answer: Also 57

Step-by-step explanation: You have to round up cause you can't type in decimals.

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2 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

7 0

2 years ago

erin has $50. she wants to purchase a cell phone ($20) and spend the rest in music cds each cd costs $8. write an inepuality for

HACTEHA [7]

She can buy 3 because 50-20=30 30/8=3.75 so u round down cause you don't have enough money to buy 4

3 0

1 year ago

What is the solution set for - 4x + 10 = 5(x + 11)? HELPPPPPPP

Scorpion4ik [409]

Answer:

-5

Step-by-step explanation:

-4x +10 =5(x +11)

-4x +10 =5x +55

-4x - 5x =55 - 10

-9x =45

x=-45 :9

x=-5

7 0

1 year ago

N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle

zmey [24]

<u>Answer-</u>

The standard error of the confidence interval is 0.63%

<u>Solution-</u>

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

$M=\frac{x}{n} =\frac{255}{2373} =0.1075$

Then the standard error SE will be,

$SE=\sqrt{\frac{M\times (1-M)}{n}}$

$SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%$

Therefore, the standard error of the confidence interval is 0.63%

6 0

2 years ago