let
x-------> walnuts that Mario eats in a week
y-------> walnuts that Yolanda eats in a week
we know that
x=2y-------> equation 1
y=6*7-------> y=42 walnuts
substitute the value of y in equation 1
so
x=2*42-----> x=84 walnuts
therefore
the answer is
Mario eat in a week 84 walnuts
Answer:
The observed tumor counts for the two populations of mice are:
Type A mice = 10 * 12 = 120 counts
Type B mice = 13 * 12 = 156 counts
Step-by-step explanation:
Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.
This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate). And the Poisson distribution gives the probability of an occurrence within a specified time interval.
You have to use the Geometric Mean for triangles to find x. Our form will look like this:
which simplifies to
. Cross multiply to get
. Therfore, x = 4. Usually when we take the square root of a number we will end up with both the principle (positive) root and the negative one as well. But since the 2 things in math that will never EVER be negative are time and distance/length, we will not consider the -4. x = 4
Answer:
Since the spinners have been spun simultaneously, every side on each of the spinner carries equal probability of landing. In order for there to be only 10 possible outcomes, no more no less, the spinners cannot be identical. One of the spinner in two sided while the other spinner must then be a five sided spinner. Choosing this particular pair of spinners gives Nathan 10 possibilities of combinations.
Hope that answers the question, have a great day!
Answer:
124.67cm³
Step-by-step explanation:
==>Given:
Dimensions of current can:
Height (h) = 12cm
Diameter = 6cm (radius = 3cm)
Volume of current can (V1) = 339.12 cm³
Dimensions of future cans to be increased multiple of 1.11:
height = 12cm × 1.11 = 13.32 cm
radius = 3cm × 1.11 = 3.33 cm
Volume of future can (V2) = πr²h = 3.14*3.33²*13.32
= 3.14*11.0889*13.32 = 463.791025
V2 ≈ 463.79 cm³
==>Find how much more would new cans hold = Volume of new can - volume of current can
= 463.79 cm³ - 339.12 cm³
= 124.67cm³
