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Sergio [31]
2 years ago
14

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.11.

If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth. 802.91 cm3 376.42 cm3 463.79 cm3 124.67 cm3

Mathematics
1 answer:
Elis [28]2 years ago
5 0

Answer:

124.67cm³

Step-by-step explanation:

==>Given:

Dimensions of current can:

Height (h) = 12cm

Diameter = 6cm (radius = 3cm)

Volume of current can (V1) = 339.12 cm³

Dimensions of future cans to be increased multiple of 1.11:

height = 12cm × 1.11 = 13.32 cm

radius = 3cm × 1.11 = 3.33 cm

Volume of future can (V2) = πr²h = 3.14*3.33²*13.32

= 3.14*11.0889*13.32 = 463.791025

V2 ≈ 463.79 cm³

==>Find how much more would new cans hold = Volume of new can - volume of current can

= 463.79 cm³ - 339.12 cm³

= 124.67cm³

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No. In many real-world scenarios, the variable is a value that is compared to other quantities. The value for the variable is used to find the quantities it is compared to.

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1 year ago
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It is believed that as many as 23% of adults over 50 never graduated from high school. We wish to see if this percentage is the
JulijaS [17]

Answer:

1)  n=48  

2) n=298

3) n=426

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\hat p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Part 1

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.10 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:  

n=\frac{0.23(1-0.23)}{(\frac{0.1}{1.64})^2}=47.63  

And rounded up we have that n=48  

Part 2

The margin of error on this case changes to 0.04 so if we use the same formula but changing the value for ME we got:

n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.64})^2}=297.7  

And rounded up we have that n=298  

Part 3

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:  

n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.96})^2}=425.22  

And rounded up we have that n=426  

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A Shampoo Problem: A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 of the bottle. How much shampoo is left? a. I
kotykmax [81]

Answer:

a) There is no a word problem for both expressions (m = 0.25\cdot 25.4 and m = 25.4-0.25), b) A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left? A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?

Step-by-step explanation:

a) The shampoo problem is a word problem for:

(Final content) = (Initial content) - (Used content)

Then,

m = 25.4 - 0.25\cdot 25.4

Or:

m = 0.75\cdot 25.4

Hence, there is no a word problem for both expressions (m = 0.25\cdot 25.4 and m = 25.4-0.25).

b) The word problem for m = 0.25\cdot 25.4 is:

A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left?

The word problem for m = 25.4-0.25 is:

A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?

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1 year ago
If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?
kiruha [24]

Answer:

[1,\infty)

Step-by-step explanation:

b(x)=\sqrt{x-4}

a(x)=3x+1

Since we want to know the domain of (b \circ a)(x), let's first consider the domain of the inside function, that is, that of a(x)=3x+1. Every polynomial function has domain all real numbers.

So we can plug anything for function a and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find (b \circ a)(x) and simplify now.

(b \circ a)(x)

b(a(x))

b(3x+1)

\sqrt{(3x+1)-4}

\sqrt{3x+1-4}

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Now again we can only square root positive or zero numbers so we want 3x-3 \ge 0.

Let's solve this to find the domain of (b \circ a)(x).

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Add 3 on both sides:

3x \ge 3

Divide both sides by 3:

x \ge 1

So we want x to be a number greater than or equal to 1.

The option that says this is [1,\infty)

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A number in the given set is -2.

a(x)=3x+1

b(x)=\sqrt{x-4}

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Give an example why option B fails:

A number in the given set is 0.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(0)=3(0)+1=0+1=1 and b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}.

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(3)=3(3)+1=9+1=10 and b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}.

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$1.21 is the original price per pound...i too am having trouble with figuring out how to setup the equation!!
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