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2 years ago

If tap and bre are supplementary and bre is its own complement, find the measure of tap. explain how you arrived at your answer

1 answer:

Pie2 years ago

3 0

Supplementary angles are those whose sum is equal to 180° while those that are complementary are those whose sum is equal to 90°. Since, we are given that bre is the complement of itself, its measure can be calculated through the equation,
m∠bre + m∠bre = 90°
m∠bre = 45°

Then, for the relationship of bre and tap, we have the equation,
m∠bre + m∠tap = 180°
45° + m∠tap = 180°
m∠tap = 135°

The measure of tap is equal to 135°.

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Select all the correct answers Which functions are the same as their inverse functions?

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Answer:

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Step-by-step explanation:

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2 years ago

Raul is practicing for baseball tryouts he wants to find how far he can hit a baseball he hits the ball 10 times and measures th

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Answer:

See Explanation

Step-by-step explanation:

Given

$n = 10$ --- Number of tryouts

Required

Determine the average distance

This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.

The mean is calculated as:

$\bar x = \frac{\sum x}{n}$

$\sum x$ means the sum of the distance in each tryout.

Assume that the distance in the 10 tryouts are: $6, 8, 5, 9, 4, 5, 8, 7, 7, 6.$

So, the mean is:

$\bar x = \frac{6+ 8+ 5+ 9+ 4+ 5+ 8+ 7+ 7+ 6}{10}$

$\bar x = \frac{65}{10}$

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So, the average distance is 6.5

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2 years ago

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Taya2010 [7]

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Answer:

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Step-by-step explanation:

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1 year ago

What is the quotient of the rational expression shown below? Make sure your answer is in reduced form. X^2+7X+10/X-2÷X^-25/4X-8

vitfil [10]

Answer:

Simplified form of $\frac{\frac{X^2+7X+10}{X-2} }{\frac{X^2-25}{X-8} } = \frac{4(X+2)}{(X-5)}$

Step-by-step explanation:

Here, the given expression is

$\frac{\frac{X^2+7X+10}{X-2} }{\frac{X^2-25}{X-8} } = \frac{P(X)}{Q(X)} \\\implies P(X) = {\frac{X^2+7X+10}{X-2} , Q(X) = \frac{X^2-25}{4X-8}$

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$(a^2 - b^2) = (a+b)(a-b)$

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$P(X) = \frac{X^2+7X+10}{X-2} = \frac{X^2+5X + 2X+10}{X-2} \\\implies P(X) = {\frac{X(X + 5) +2(X+5)}{X-2} \\= P(X) = {\frac{(X+ 5)(X+2)}{X-2} \\\\\implies P(X) = {\frac{(X+ 5)(X+2)}{X-2}$

Similarly, Q(X) = $\frac{X^2-25}{4X-8} = \frac{(X-5)(X+5)}{4X-8} \\\implies Q(X) = \frac{(X-5)(X+5)}{4(X-2)}$

hence, the given fraction is simplified to

$\frac{P(X)}{Q(X)} = \frac{\frac{(X+ 5)(X+2)}{(X-2)} }{\frac{(X-5)(X+5)}{4(X-2)} }$

$\implies \frac{P(X)}{Q(X)} = \frac{\frac{(X+ 5)(X+2)}{(X-2)} }{\frac{(X-5)(X+5)}{4(X-2)} } ={\frac{(X+ 5)(X+2)}{(X-2)} } \times {\frac{ 4(X-2)}{(X-5)(X+5)} = \frac{4(X+2)}{(X-5)}$

Hence, the simplified form of $\frac{\frac{X^2+7X+10}{X-2} }{\frac{X^2-25}{X-8} } = \frac{4(X+2)}{(X-5)}$

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