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1 year ago

If tap and bre are supplementary and bre is its own complement, find the measure of tap. explain how you arrived at your answer

1 answer:

Pie1 year ago

3 0

Supplementary angles are those whose sum is equal to 180° while those that are complementary are those whose sum is equal to 90°. Since, we are given that bre is the complement of itself, its measure can be calculated through the equation,
m∠bre + m∠bre = 90°
m∠bre = 45°

Then, for the relationship of bre and tap, we have the equation,
m∠bre + m∠tap = 180°
45° + m∠tap = 180°
m∠tap = 135°

The measure of tap is equal to 135°.

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The local pizza shop sells several special items.

Anna35 [415]

Answer:

Tax for Italian Salad=$0.20

Tax for Lasagna= $0.43

Tax for Spaghetti =$0.21

Tax for Fettuccini Alfredo =$0.36

Step-by-step explanation:

Hi, to answer this question we have to multiple the price of each item by the tax percentage in decimal form (divided by 100):

Italian Salad =$3.99

Tax for Italian Salad= 3.99 x (5/100) = 3.99 x 0.05 =$0.20

Lasagna =$8.50

Tax for Lasagna= 8.50 x (5/100) = 8.50 x 0.05 =$0.43

Spaghetti =$4.29

Tax for Spaghetti = 4.29x (5/100) = 4.29 x 0.05 =$0.21

Fettuccini Alfredo =$7.17

Tax for Fettuccini Alfredo = 7.17 x (5/100) = 7.17 x 0.05 =$0.36

Feel free to ask for more if needed or if you did not understand something.

6 0

1 year ago

Read 2 more answers

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

1 year ago

A pebble is tossed into the air from the top of a cliff. The height, in feet, of the pebble over time is modeled by the equation

Charra [1.4K]

Answer:

Step-by-step explanation:

The maximum height reached by the pebble modeled by the quadratic function,

$h(t)=-16t^2+32t+80$ , can be found by finding the vertex.

Let's first find the t-coordinate of the vertex . The max height will correspond to this value of t which means we have to find the h(t)-coordinate.

When comparing $h$ to $at^2+bt+c$ , we see that:

$a=-16$

$b=32$

$c=80$

We need to evaluate the following to find the t-coordinate of the vertex:

$t=\frac{-b}{2a}$

$t=\frac{-32}{2(-16)}$

$t=\frac{-32}{-32}$

$t=1$

So now to find the correspond h(t)-coordinate, we will need to replace t in $-16t^2+32t+80$ with 1:

$-16(1)^2+32(1)+80$

$-16(1)+32+80$

$-16+32+80$

$16+80$

$96$

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1 year ago

As a computer technician, Andre makes $20 per hour to diagnose a problem and $25 per hour to fix a problem. He works fewer than

irinina [24]

For
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope

yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint

x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10

since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line

x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below

test point (4,5)

20(4)+25(5)≥200
80+125≥200
225≥200
true

4+5<10
9<10
true

so the ones that are true are

The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).

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1 year ago

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Dafna11 [192]

Answer:

0.6 is the diference

Step-by-step explanation:

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1 year ago