Find -34 + 15 - 29

Marisol is making a rectangular wooden frame. She wants the length of the frame to be no more than 12 inches. She has less than

svlad2 [7]

The perimeter of a rectangle is
2l + 2w
This has to be less than 30 because she has less than 30 inches of wood altogether.
The length must also be "no more than", which means less than or equal to, 12 inches.
Option A satisfies both of these conditions.

5 0

2 years ago

If g(x) = 2x + 2 and h(x) = 4x2 + 8x + 8, find a function f such that f ∘ g = h. (Think about what operations you would have to

agasfer [191]

Answer:

Step-by-step explanation:

Hello,

$(\forall x \in \mathbb{R}) (fog)(x)=f(g(x))=f(2x+2)=h(x)=4x^2+8x+8\\\\=(2x+2)^2-2^2+4(2x+2)\\\\=(2x+2)^2+4(2x+2)-4\\\\\text{So, we conclude by.}\\\\\large \boxed{\sf \bf f(x)=x^2+4x-4}$

7 0

1 year ago

Maggie bought 3/4 of a pound of bananas and 4 boxes of cereal for $10.11. If each box of cereal cost $2.40, what was the price o

beks73 [17]

If you had 4 boxes of cereal and each costs $2.40, the total cost would be $9.60 (2.40×4).

The total cost of the bananas and the cereal cost $10.11. To find how much the 3/4 of bananas cost, simply subtract $9.60 away from $10.11 (10.11-9.6), which gives you $0.51.

The question asks for 1 pound of bananas but you only have the cost of 3/4. So, divide your cost by 3 to give you the cost of 1/4. (0.51÷3), which gives you $0.17.

The last step is to multiply this answer by 4 because 4/4 will result in a whole, or in this case, one pound (0.17×4) and thus gives you the cost $0.68 for one pound of bananas.

(please correct me if I'm wrong, hope this helped c: )

6 0

2 years ago

Read 2 more answers

The radius of a cylindrical construction pipe is 1.5ft . If the pipe is 14ft long, what is its volume? Use the value 3.14 for π

Lady bird [3.3K]

Answer:

Volume of cylinder =989 ft cube

Step-by-step explanation:

Volume of cylinder

Volume V = πr²h

r - radius and h - height

It is given that,

The radius of a cylindrical construction pipe is 1.5ft and

Length of pipe = 14 ft

To find volume of cylinder

Volume V = πr²h

V = 3.14 x 1.5 x1.5 x 14 =989.1 ≈ 989 ft cube

5 0

1 year ago

A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F

Dima020 [189]

Answer:

(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

Step-by-step explanation:

The complete question is:

A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is

(a) exactly 5

(b) 2 or fewer

(c) more than 1.

Let X = number of unspoiled eggs in the bad carton of eggs.

Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.

The probability of selecting an unspoiled egg is:

$P(X)=p=\frac{10}{18}=0.556$

A randomly selected egg is unspoiled or not is independent of the others.

It is provided that a chef picks 5 eggs at random.

The random variable X follows a Binomial distribution with parameters n = 5 and p = 0.556.

The success is defined as the selection of an unspoiled egg.

The probability mass function of X is given by:

$P(X=x)={5\choose x}(0.556)^{x}(1-0.556)^{5-x};\ x=0,1,2,3...$

(a)

Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:

$P(X=5)={5\choose 5}(0.556)^{5}(1-0.556)^{5-5}\\=1\times 0.05313\times 1\\=0.0531$

Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b)

Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

$=\sum\imits^{2}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=0.0173+0.1080+0.2706\\=0.3959$

Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c)

Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\sum\limits^{1}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=1-0.0173-0.1080\\=0.8747$

Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

6 0

2 years ago

Find -34 + 15 - 29 - (-3)