The houses can be placed in 362,880 ways.
<u>Step-by-step explanation:</u>
The 9 houses are each in different design.
The each lot can place any of the 9 houses.
- The 1st lot can place anyone house of all the 9 houses.
- The 2nd lot can place one of remaining 8 houses.
- The 3rd lot can place one of remaining 7 houses.
Similarly, the process gets repeated until the last house is placed on a lot.
<u>From the above steps, it can be determined that :</u>
The number of ways to place the 9 houses in 9 lots = 9!
⇒ 9×8×7×6×5×4×3×2×1
⇒ 362880 ways.
Therefore, the houses can be placed in 362880 ways.
6hrs = school
9hrs = sleeps = 18hrs // 24hrs ----6hrs left
3hrs = plays
6hrs = other things
playing = 12.5% -- 3/24 3/24*100
other things = 25% -- 6/24 6/24*100
Answer:
True
0.08 km/ 1 min = 1 mi = 1.61 km
answer rounds to 0.05
Answer:
The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
Step-by-step explanation:
The data provided is as follows:
25 to 34 45 to 54
1329 2268
1906 1965
2426 1149
1826 1591
1239 1682
1514 1851
1937 1367
1454 2158
Compute the mean and standard deviation for the group "25 to 34" as follows:
![\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%20x%3D%5Cfrac%7B1%7D%7B8%7D%5Ctimes%20%5B1329%2B1906%2B...%2B1454%5D%3D%5Cfrac%7B13631%7D%7B8%7D%3D1703.875%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B8-1%7D%5Ctimes%201086710.875%7D%3D394.01)
Compute the <em>z</em>-score for the group "25 to 34" as follows:
Compute the mean and standard deviation for the group "45 to 54" as follows:
![\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%20x%3D%5Cfrac%7B1%7D%7B8%7D%5Ctimes%20%5B2268%2B1965%2B...%2B2158%5D%3D%5Cfrac%7B14031%7D%7B8%7D%3D1753.875%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B8-1%7D%5Ctimes%201028888.875%7D%3D383.39)
Compute the <em>z</em>-score for the group "45 to 54" as follows:
Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
s(t) = 65+24sin(0.3t)
where t is measured in hours since 5:00
a.m
3-hour period from 7:00 a.m. to 10:00 am
5 am to 7 am = 2 hours
5 am to 10 am = 5 hours
To find the number of tons we take integral of 2 to 5 of s(t)
∫ 2 to 5 s(t) = ∫ 2 to 5 (65+24sin(0.3t))
∫65+24sin(0.3t) dt = 65t - 80 cos(0.3t) + c
Now we plug in the bounds 2 and 5
∫ 2 to 5 (65+24sin(0.3t)) = 255.36787 = 255.268
255.268 tons of sand are added to the beach over the 3-hour period
