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2 years ago

Which graph represents a bike traveling at a constant rate of 12 miles per hour

Mathematics

2 answers:

mrs_skeptik [129]2 years ago

8 0

The third graph if I am correct

Sholpan [36]2 years ago

5 0

The third graph because after one hour the graph has a point on the number 12 and after two hours the graph has a point in the number 24 and on the third hour the graph has a point on number 32.

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Mr. Trager has $600.00 to spend at a bicycle store

Snowcat [4.5K]

Answer:

Step-by-step explanation:

Total money = $600

Bicycle cost = $253.98

3 bicycle reflector = 3×$7.5 =$22.5

Bicycle helmet = $42.36

Total money spent will be equal to the = $(253.98+22.5+42.36)

= $318.84

Amount remaining = $(600-318.84)

= $281.16

The number of outfit he can get at $78.12 = $281.16/78.12 = 3.60

He can get 3 outfit and have $0.60

Left

7 0

2 years ago

Read 2 more answers

Twenty-five juniors from a University volunteer to allow their Math GRE test scores to be used in a study. These 25 juniors had

fgiga [73]

Let's start first by writing down the given:
σ = 100
sample mean = 450
sample size = 25

These information, plus the fact that we know that the population is approximately normally distributed, would tell us that we can use the normal distribution curve in analyzing the problem.

A confidence interval of the mean is just a range statistically estimated to contain the population mean. For a 90% confidence interval, we would look at the Z-table and see where 90% of the data falls. We'll notice that it will fall within 1.645 standard deviations of the mean.

Next, we look for the standard error of the mean. This will have a formula
$error= \frac{standard deviation of population}{ \sqrt{N} }$

The standard error would just therefore be equal to
$\frac{100}{ \sqrt{25} }= \frac{100}{5} =20$

Lastly, we just get the product of the standard error and 1.645 and add it to 450 for the maximum value and subtract it to 450 for the minimum value.
$450-20(1.645)=417.1$
$450+20(1.645)=482.9$

ANSWER: 417.1<μ<482.9

8 0

2 years ago

a(0.3−y)+1.1+2.4x (y−1.2) =0 =−1.2(x−0.5) Consider the system of equations above, where aaa is a constant. For which value o

Veseljchak [2.6K]

Answer:

For a = 1.22 there is one solution where y = 1.3

Step-by-step explanation:

Hi there!

Let´s write the system of equations:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

-1.2(x-0.5) = 0

Let´s solve the second equation for x:

-1.2(x-0.5) = 0

x- 0.5 = 0

x = 0.5

Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0

a(-1) + 1.1 + 1.2(0.1) = 0

-a + 1.22 = 0

-a = -1.22

a = 1.22

Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:

1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0

0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0

-0.02y +0.026 = 0

-0.02y = -0.026

y = -0.026 / -0.02

y = 1.3

Then, the answer is correct.

Have a nice day!

4 0

2 years ago

Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract

serg [7]

Answer:

$x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}$

Step-by-step explanation:

Given:

The equation to solve is given as:

$x^2=-5x+8$

Rearrange the given equation in standard form $ax^2+bx +c =0$ , where, $a,\ b,\ and\ c$ are constants.

Therefore, we add $5x-8$ on both sides to get,

$x^2+5x-8=0$

Here, $a=1,b=5,c=-8$

The solution of the above equation is determined using the quadratic formula which is given as:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Plug in $a=1,b=5,c=-8$ and solve for $x$ .

$x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}$