All categories

1 year ago

Mr. Trager has $600.00 to spend at a bicycle store

Mathematics

2 answers:

Snowcat [4.5K]1 year ago

7 0

Answer:

Step-by-step explanation:

Total money = $600

Bicycle cost = $253.98

3 bicycle reflector = 3×$7.5 =$22.5

Bicycle helmet = $42.36

Total money spent will be equal to the = $(253.98+22.5+42.36)

= $318.84

Amount remaining = $(600-318.84)

= $281.16

The number of outfit he can get at $78.12 = $281.16/78.12 = 3.60

He can get 3 outfit and have $0.60

Left

eduard1 year ago

3 0

Answer:

Step-by-step explanation:

Mr.Trager have $600.00

1.New bicycle $253.98

2.3 bicycle reflectors $7.50 each which will give him $22.50

3.1 bicycle helmet $42.36

4.Then I add all his spending money's together,which give him $318.84

5.substract $318.84 in $600.00 which will give $281.16

6.then use a calculator to know how many outfit can he obtain in $281.16*

*divide $281.16 by 78.12 ,which give 3.599078341 so THE ANSWER IS 3 OUTFITS.

You might be interested in

Esteban is reading a book with 16 pages. He has read 9 pages so far. How many pages does Esteban have left to read? Write two eq

Zielflug [23.3K]

Answer:

7 pages

Step-by-step explanation:

Given the total number of pages in the book are 16

The number of pages esteban already read are 9

Let the number of pages left out to read be x

Total number of pages = number of pages read + number of pages to be read

16=9+x

x=16-9

x=7 pages

Therefore There are 7 pages left out to be read.

8 0

1 year ago

Arc CD is One-fourth of the circumference of a circle. What is the radian measure of the central angle?

Alex

Answer:

$\frac{\pi }{2}$

Step-by-step explanation:

Since the arc is $\frac{1}{4}$ of the circumference, then

central angle = $\frac{1}{4}$ × 2π ← angle in whole circle

central angle = $\frac{2\pi }{4}$ = $\frac{\pi }{2}$

8 0

2 years ago

Add 4 to n then divide by 5

Ket [755]

The equation used for this is

$\frac{(4+n)}{5}$ =

if you knew n then we could solve this equation

4 0

1 year ago

A liquid dietary product implies in its advertising that use of the product for one month results in an average weight loss of a

BigorU [14]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Please find the table in the attached file.

mean and standard deviation difference: $\bar{d}=\frac{\Sigma d}{n} =\frac{-4-6-.......-4-4}{8}=-4.125 \\\\S_d=\sqrt{\frac{\Sigma (d-\bar{d})^2 }{n-1}}=\sqrt{\frac{(-4 + 4.125)^2 +.......+(-4 +4.125)^2 }{8-1}}= 1.246$

For point a:

hypotheses are:

$H_0 : \mu_d \geq -3\\\\H_a : \mu_d < -3\\\\$

degree of freedom:

$df=n-1=8-1=7$

From t table, at $\alpha = 0.05$ , reject null hypothesis if $t$ .

test statistic:

$t=\frac{\bar{d}-\mu_d }{\frac{s_d}{\sqrt{d}}}=\frac{ -4.125- (-3)}{\frac{1.246}{ \sqrt{8}}} =-2.55$

because the $t=-2.553$ , removing the null assumption. Data promotes a food product manufacturer's assertion with a likelihood of Type 1 error of 0.05.

For point b:

From t table, at $\alpha =0.01$ , removing the null hypothesis if $t$ .

because $t=-2.553 >-2.908$ , fail to removing the null hypothesis.

The data do not help the foodstuff producer's point with the likelihood of a .01-type mistake.

For point c:

Hypotheses are:

$H_0: \mu_d \geq -5\\\\H_a: \mu_d < -5$

Degree of freedom:

$df=n-1=8-1=7$

From t table, at $\alpha =0.05$ , removing the null hypothesis if $t$ .

test statistic: $t=\frac{\bar{d}-\mu_d}{\frac{s_d}{\sqrt{n}}} =\frac{-4.125-(-5)}{\frac{1.246}{\sqrt{8}}}=1.986$

Since $t-1.986 >-1.895$ , The null hypothesis fails to reject. The results do not support the packaged food producer's claim with a Type 1 error probability of 0,05.