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Lynna [10]
1 year ago
9

Jon is hanging a picture. He wants to center it horizontally on the wall. The picture is 32 1/2 inches long, and the wall is 120

3/4 inches long. How far from each edge of the wall should he place the picture? Please answer quickly.
Mathematics
1 answer:
frozen [14]1 year ago
8 0

Answer:

44.125 inches

Step-by-step explanation:

Given that:

Length of picture = 32 1/2 inches

Length of wall = 120 3/4 inches

Hence, to center picture horizontally ;

Distance from the edge of the wall in which the picture should be placed :

(Length of wall - length of picture) / 2

(120 3/4 - 32 1/2) / 2

(483/4 - 65/2) / 2

Take the L. C. M of 4 and 2 = 4

((483 - 130) / 4) ÷ 2

(353 / 4) ÷ 2

(353 / 4) * (1 / 2)

= 353 / 8

= 44 1/8

= 44 1/8

= 44.125 inches

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The most popular mathematician in the world is throwing aparty for all of his friends. As a way to kick things off, they decidet
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Answer:

The no. of possible handshakes takes place are 45.

Step-by-step explanation:

Given : There are 10 people in the party .

To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?

Solution:

We are given that there are 10 people in the party

No. of people involved in one handshake = 2

To find the no. of possible handshakes between 10 people we will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

n = 10

r= 2

Substitute the values in the formula

^{10}C_{2}=\frac{10!}{2!(10-2)!}

^{10}C_{2}=\frac{10!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 \times 8!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 }{2 \times 1}

^{10}C_{2}=45

No. of possible handshakes are 45

Hence The no. of possible handshakes takes place are 45.

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Nestor works at a garden center where he pots plants. It take's him 2 1/2 hours to pot 15 plants.
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6 per hour

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Timothy explains to his brother that the model y=4mt has a constant of variation of 4 and is an example of _____ variation.
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The cable company charges $30 to install new supplies at your house. Each month the cable bill is $75. Which equation models the
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Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.
lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

                            2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2

Lets divide the expression by 2x^2\:-\:3x\:+\:1

Solution Steps:

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}

Factorizing

2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}

Factorizing

2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}

\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2

x^2+5x-2

Thus,

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

3 0
1 year ago
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