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sergij07 [2.7K]
2 years ago
15

Tim must choose 4 graphic novels out of a collection of 13 to take on vacation.

Mathematics
2 answers:
Vsevolod [243]2 years ago
7 0

C(13,4)=\dfrac{13!}{4!9!}=\dfrac{10\cdot11\cdot12\cdot13}{2\cdot3\cdot4}=715

Kay [80]2 years ago
7 0

there are 715 ways to choose (C, 715)

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Mark and his friends ordered two pizzas are the same size the first pizza is cut into six slices of equal size the second pizza
tino4ka555 [31]

1/6 < 1/4 so 1/6 would equal 2/12 and 1/4 would equal 3/12 so which means if you take one from each it would be 5/12 but if you took 2 from the first one it would only be 2/12 which is why you need to read correctly because THE REASON MARK IS CORRECT IS BECAUSE 5/12 IS GREATER THAN 2/12

3 0
2 years ago
If Bianca is trying to find the area of this rectangle. She already measured one side 10cm. Witch other length(s) could she meas
slavikrds [6]
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8 0
2 years ago
A student raises her grade average from a 75 to a 90. What was the percent of increase
son4ous [18]
This can be solved algebraically. Before we start, as context, to find a percentage you multiply by the percentage/100.

75*x=90 \\ x= \frac{90}{75}  \\  \\ \boxed{x=1.2}

This tells us that 90 is 120% of 75. However, your question wants us to find the <em>increase</em>, therefore we don't need that 100.
Therefore, the increase is 20%.
4 0
2 years ago
A copper smelting process is supposed to reduce the arsenic content of the copper to less than 1000 ppm. let μ denote the mean a
Hitman42 [59]
The rejection region is give by 

|z_{test}|\ \textgreater \ z_{\alpha/2}

where the test statistics is given by

\frac{\bar{x}-\mu}{\sigma/\sqrt{n}} = \frac{980-1000}{100/\sqrt{75}} \\ \\ = \frac{-20}{100/8.6603} = \frac{-20}{11.5470} =-1.73

i.e. |z_{test}|=|-1.73|=1.73

Thus, z_{\alpha/2}=1.73

Using the statistical table, the level of the test is 0.04.
6 0
2 years ago
. Given f(x) = e 2x e 2x + 3e x + 2 : (a) Make the substitution u = e x to convert Z f(x) dx into an integral in u (HINT: The ea
MrRa [10]

Answer:

Step-by-step explanation:

Given;

f(x)=\frac{e^{2x}}{e^{2x}+3e^x+2}

a)

substitute u=e^x\\du=e^x dx\\\\\int\frac{e^{2x}}{e^{2x}+3e^x+2}dx=\int\frac{e^x\dot e^x}{e^x^{2x}+3e^x+2}dx\\\\=\int\frac{udu}{u^2+3u+2}

b)

Apply partial fraction in (a), we get;

\frac{u}{u^2+3u+2}=\frac{2}{u+2}-\frac{1}{u+1}\\\\\therefore u^2+3u+2\\=u^2+2u+u+2\\=u(u+2)+1(u+1)\\=(u+2)(u+1)\\\\Now\,\int\frac{u}{u^2+3u+2}\,du=\int\frac{2}{u+2}du-\int\frac{1}{u+1}du\\\\=2ln|u+2|-ln|u+1|+c\\=2ln|e^x+2|-lm|e^x+1|+c

where C is an arbitrary constant

8 0
2 years ago
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