martin cycles from home yo a town in five hours at an average speed of 15km/h. find the distance he cycle

The annual interest rate of Daphne's savings account is 2.4% and simple interest is calculated semiannually. What is the periodi

alexdok [17]

The interest rate is calculated semiannually which means twice a year so you do 2.4/2 which equals 1.2 so the answer is D

4 0

2 years ago

Gwen buys 3 identical pairs of shoes at Store a. She pays $110.25 after the discount. what is the original price of each pair?

emmasim [6.3K]

In perspective this looks tricky but really its no ;) just follow it slowly.
110.25 is your total cost
3 is how many you bought.
So doing division 3/110.25= 36.75
CHECK: 36.75 + 36.75 + 36.75 = 110.25.
Hope this helps.

5 0

1 year ago

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You are paying all eight of your monthly recurring bills free online now that you used to pay by "snail-mail". Stamps cost 47 ce

Ede4ka [16]

Answer:

$45.12

Step-by-step explanation:

($0.47 /stamp)×(8 stamps/mo)×(12 mo/yr) = $45.12 /yr

You will save $45.12 per year on stamps.

8 0

1 year ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

1 year ago

100 POINTS! IF YOU ANSWER THESE 5 QUESTIONS CORRECTLY :)

Sergeeva-Olga [200]

1. Use a computer to randomly select 30 student IDs from all her students2. If the ice cream store owner asks 2300 people, will most likely pick cheesecake to be the flavor of the month.3. I would need the line plot4. I would need the graph to solve5. I would need the graph to solveClick to let others know, how helpful is it

Read more on Brainly.com - brainly.com/question/3239357#readmore

5 0

1 year ago

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martin cycles from home yo a town in five hours at an average speed of 15km/h. find the distance he cycle​

martin cycles from home yo a town in five hours at an average speed of 15km/h. find the distance he cycle