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aleksley [76]
2 years ago
12

Janet and Nadia each play basketball, Nadia has won twice the number of games Janet has, Is it possible for Janet to have won 10

games if the sum of the games
Nadia and Janet have won together is 24?
Mathematics
1 answer:
Lapatulllka [165]2 years ago
4 0

Answer:

It is not possible for Janet to have won 10 games.

Step-by-step explanation:

Let be "x" the number of games Janet won.

We know that Nadia has won twice the number of games Janet has and the sum of the games Nadia and Janet have won together is 24.

Then, we express this situation with this equation:

So, let's check if it is possible for Janet to have won 10 games. Substitute  into the expression:

Therefore, it is not possible for Janet to have won 10 games.

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If f(t)= 3t^2-2, find f(k-2)
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By plugging (k-2) in t, we can write that
f(k-2)=3(k-2)^{2}-2=3(k^{2}-4k+4)-2=3 k^{2}-12k+12-2=3 k^{2}-12k+10
7 0
2 years ago
Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x
konstantin123 [22]
First, she distributed 3*x=3x , 3*4=12, 5*x= 5x, 5* -4= -20
Which gave her 3x+12+2=2+5x-20
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Which gave her 3x+14=5x-18
Then, she subtracted 3x from both sided 
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Then, she added 18 to both sides
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5 0
2 years ago
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An episode of the television show, Legend of the Far Mountain, normally lasts 30 minutes and has 8 minutes of commercials. Tonig
gizmo_the_mogwai [7]
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2 years ago
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Which expression is equivalent to the following complex fraction?
marta [7]

Answer:

  \dfrac{-4x+7}{2(x-2)}

Step-by-step explanation:

The first step is to combine the parts of the numerator and denominator into one rational expression each. Those will have the same denominator, so their ratio is the ratio of their numerators.

  \dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}=\dfrac{3-4(x-1)}{2(x-1)-2}\\\\=\dfrac{3-4x+4}{2x-2-2}=\boxed{\dfrac{-4x+7}{2(x-2)}}

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2 years ago
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Nico makes annual end-of-year payments of $5,043.71 on a four-year loan with an interest rate of 13 percent. The original princi
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We need to find the principal amount on an interest rate of 13% where the end of year payment is $5043.71.

The original amount is \$15002.37.

i = Interest rate = 13%

n = Compounding period = 4 years

E = End of year payment = $5043.71

The required formula is

P=\dfrac{E[1-(1+i)^{-n}]}{i}\\\Rightarrow P=\dfrac{5043.71[1-(1+0.13)^{-4}]}{0.13}\\\Rightarrow P=\$15002.37

The original principal amount was \$15002.37.

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