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2 years ago

In a 14-game season, a football team

Mathematics

2 answers:

stealth61 [152]2 years ago

8 0

Answer:

13 scored = 1/7 ≈14.3%

27 scored = 1/7 ≈14.3%

33 scored =2/7 ≈28.6%

48 scored =3/7 ≈ 42.9%

Step-by-step explanation:

Probability of getting 13 scored in a game = 2/total possible outcomes = 2/14 = 1/7

Probability of getting 27 scored in a game = 2/total possible outcomes = 2/14 = 1/7

Probability of getting 33 scored in a game = 4/total possible outcomes = 4/14 = 2/7

Probability of getting 48 scored in a game = 6/total possible outcomes = 6/14 = 3/7

Brums [2.3K]2 years ago

3 0

Median:the middle number of the set of numbers

Median in this set of numbers is 30.

What I did was used my fingers to cover the first and last number of the set (13 and 48) then move in but in this case if I cover 27 and 33 then we can't find the median so I wrote the set of numbers from 27 to 33 (27,28,29,30,31,32,33) then I did the same thing with my fingers and the median is 30.

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12. If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that th

atroni [7]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

$Confidence= 0.95$ the confidence level desired

$ME =0.03$ represent the margin of error desired

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The confidence level is 95% or 0.95, the significance is $\alpha=0.05$ and the critical value for this case using the normal standard distribution would be $z_{\alpha/2}=1.96$

Since we don't have prior information we can use $\hat p= 0.5$ as an unbiased estimator

Also we know that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

6 0

1 year ago

The list shows the area in square feet of each apartment available for rent in a building. 565, 961, 867, 517, 627, 714, 517, 72

gladu [14]

STEP 1:
put numbers in order from lowest to highest
517, 517, 565, 627, 714, 728, 867, 961

STEP 2:
find the difference between the lowest and highest numbers

961 - 517= 444 ft^2 range

ANSWER: The range of the areas is 444 ft^2.

Hope this helps! :)

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2 years ago

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Which expressions can you use to find 75% of 56? Check all that apply.

alisha [4.7K]

Your answer would be B and C

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Reika [66]

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