Question

In a 14-game season, a football team

Answer 1

Answer:

13 scored = 1/7 ≈14.3%

27 scored = 1/7 ≈14.3%

33 scored =2/7 ≈28.6%

48 scored =3/7 ≈ 42.9%

Step-by-step explanation:

Probability of getting 13 scored in a game = 2/total possible outcomes = 2/14 = 1/7

Probability of getting 27 scored in a game = 2/total possible outcomes = 2/14 = 1/7

Probability of getting 33 scored in a game = 4/total possible outcomes = 4/14 = 2/7

Probability of getting 48  scored in a game = 6/total possible outcomes = 6/14 = 3/7

Answer 2

Median:the middle number of the set of numbers

Median in this set of numbers is 30.

What I did was used my fingers to cover the first and last number of the set (13 and 48) then move in but in this case if I cover 27 and 33 then we can't find the median so I wrote the set of numbers from 27 to 33 (27,28,29,30,31,32,33) then I did the same thing with my fingers and the median is 30.