Step-by-step explanation
<h3>
Prerequisites:</h3>
<u>You need to know: </u>



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Division of two quantities is expressed as the quotient of those two quantities.
The word quotient is derived from the Latin language. It is from the Latin word "quotiens" which means "how many times." A quotient is the answer to a divisional problem. A divisional problem describes how many times a number will go into another. The first time that this word was known to have been used in mathematics was around 1400 - 1500 AD in England.
There are two different ways to find the quotient of two numbers. One of them is through Fractions. The quotient of a fraction is the number obtained when the fraction is simplified. The other way to find a quotient is by employing the long division method where the quotient value is positioned above the divisor and dividend.
Answer:

Step-by-step explanation:
<u>Find the measures of interior angles in each triangle</u>
Triangle BGC

The measures of triangle BGC are 
Triangle CGH
we know that
-----> by consecutive interior angles
we have that
so

substitute

we have



remember that




The measures of triangle CGH are 
Triangle GHE


remember that

substitute and solve for m<GEH



The measures of triangle GHE are 
D + 3r = 15
d = r + 3
r + 3 + 3r = 15
4r + 3 = 15
4r = 15 - 3
4r = 12
r = 12/4
r = 3 ....he bought 3 roses, at $ 3 per rose = $ 9 <==
d = r + 3
d = 3 + 3
d = 6....he bought 6 daisies, at $ 1 per daisy = $ 6
A geometric series is written as
, where
is the first term of the series and
is the common ratio.
In other words, to compute the next term in the series you have to multiply the previous one by
.
Since we know that the first time is 6 (but we don't know the common ratio), the first terms are
.
Let's use the other information, since the last term is
, we know that
, otherwise the terms would be bigger and bigger.
The information about the sum tells us that

We have a formula to compute the sum of the powers of a certain variable, namely

So, the equation becomes

The only integer solution to this expression is
.
If you want to check the result, we have

and the last term is
