Wheel A will travel a distance of approximately 9 in more than wheel B in one rotation.
<u>Explanation:</u>
Given:
Diameter of wheel A, d₁ = 25.4 in
Radius of wheel A, r₁ = 12.7 in
Diameter of wheel B = 22.5 in
Radius of Wheel B, d₂ = 11.25 in
Distance travelled by A = ?
In one rotation, the distance travelled by a wheel is equal to its circumference.
Circumference of a wheel = 2πr
Circumference of wheel A = 2πr₁
= 2 X 3.14 X 12.7 in
= 80 in
Circumference of wheel B = 2πr₂
= 2 X 3.14 X 11.25 in
= 71 in
Therefore, wheel A will travel a distance of approximately 9 (80 - 71 in) in more than wheel B in one rotation.
Answer:
Sabemos que:

y tenemos que:

Con esto podemos encontrar el valor de a:
8*a/(a+ 4) = 6
8*a = 6*(a + 4) = 6*a + 24
8a - 6a = 24
2a = 24
a = 24/2 = 12.
Tambien sabemos que:

Y de ahí podemos despejar b:
(16*b)/(b + 8) = 12
16*b = 12*(b + 8) = 12b + 96
16b - 12b = 96
4b = 96
b = 96/4 = 24
Entonces tenemos a = 12 y b = 24, y el MH de a y b es:
MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16


Synthetic division yields
-3 | 1 5 4 -6
. | -3 -6 6
- - - - - - - - - - - - -
. | 1 2 -2 0
which translates to

with remainder 0. Now by the quadratic formula,

and so
The maximum height of the baseball. Hope this helped :)
Answer:
1184000
Step-by-step explanation:
lcm(2960,6400,2000)
prime factor:

Take the largest power of each factor:
