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2 years ago

What is log6^e f rewritten using the power property?

2 answers:

8 0

$\bf \textit{Logarithm of exponentials}\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
log_6(e^f)\implies flog_6(e)$

marishachu [46]2 years ago

4 0

Given expression : $log_6e^f .$ .

We need to apply power property of logs to rewrite it.

According to log rule of exponents:

$log_b a^n = n log_b(a)$

If we compare given expression with the rule the exponent part is f, base is 6.

Therefore, we need to bring exponent f in front of log.

Therefore, $log_6e^f = flog_6 e$ .

<h3>And correct option is second option $flog_6 e.$ </h3>

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2 years ago

Suppose 50 percent of the customers at Pizza Palooza order a square pizza, 70 percent order a soft drink, and 35 percent order b

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Given: P(A)=0.5 & P(B)=.7

P(A∩B) = P(A) × P(B)

= 0.5 × .7

= 0.35

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.5 + .7 - 0.35

= 0.85

P(AΔB) = P(A) + P(B) - 2P(A∩B)

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= 0.5

P(A') = 1 - P(A)

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= 0.5

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2 years ago

Jing spent 1/3 of her money on a pack of pens, 1/2 of her money on a pack of markers, and 1/8 of her money on a pack of pencils.

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As per the problem

Jing spent $\frac{1}{3}$ of her money on a pack of pens.

$\frac{1}{2}$ of her money on a pack of markers.

and $\frac{1}{8}$ of her money on a pack of pencils.

Total fraction of money spent cab be given as below

Fraction of Money Spent = $\frac{1}{3} +\frac{1}{2}+\frac{1}{8}$

Take the LCD of denominator, we get LCD of (3,2,8)=24

Fraction of Money Spent = $\frac{8+12+3}{24} =\frac{23}{24} \\\\$

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2 years ago

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