Ask question

Ask question

All categories

soldi70 [24.7K]

2 years ago

12

A side of a regular six - sided polygon is 8cm long. The perimeter of a similar polygon is 60cm. What is the length of a side of

the larger polygon?

1 answer:

Lerok [7]2 years ago

4 0

Answer:

10 cm

Step-by-step explanation:

The larger polygon is also a regular 6-sided polygon, so each side is 1/6 of the perimeter length:

(60 cm)/6 = 10 cm . . . length of a side

You might be interested in

He repartido mi colección de canicas entre mis tres amigos. A thales le he dado 1/5 del total, a arquimedes un 1/3 del resto y p

elena-14-01-66 [18.8K]

Answer:

Ok, supongamos que en total hay N canicas.

1/5 de esas canicas se le dieron a Thales.

Entonces el resto ahora es:

1 - 1/5 = 4/5.

1/3 de esas canicas se le dieron a Arquimedes.

Entonces Arquimedes recibe:

(1/3)(4/5) = 4/15 de las canicas totales.

El resto, que eran 16, se le dieron a Pitagoras.

Ahora, las dos primeras entregas fueron:

1/5 + 4/15 = 3/15 + 4/15 = 7/15.

El resto seria:

1 - 7/15 = 8/15.

Y sabemos que el resto es igual a 16 canicas, entonces tenemos que:

(8/15)*N = 16.

De aca podemos calcular el numero total de canicas.

N = 16*(15/8) = 30

Esto quiere decir que inicialmente hay 30 canicas.

Thales recibe 30*(1/5) = 7 canicas.

Arquimedes recibe 30*(4/15) = 8 canicas.

Pitagoras recibe 16 canicas.

4 0

2 years ago

A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is

MakcuM [25]

Answer:

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 5 minutes

Sample mean, $\bar{x}$ = 4.61 minutes

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.75 minutes

a) First, we design the null and the alternate hypothesis

$H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}$

We use two-tailed t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.61 - 5}{\frac{0.75}{\sqrt{15}} } = -2.0139$

c) Now, we calculate the p-value using the standard table.

P-value = 0.0638

d) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Option a) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05.

4 0

2 years ago

You fold a banner that is 3 ft long into 7 equal sections for shipping. find the length of

Alexandra [31]

Gonna be somewhere about 5 inches if I’m correct I hope this helps:)

6 0

2 years ago

The owner of a Farmer’s Market wants to construct a triangular fruit stand in his store. Use the diagram below and the Law of Si

Lera25 [3.4K]

Hello,
Please, see the attached file.
Thanks.

7 0

2 years ago

Read 2 more answers

State the complement of each of the following sets: (a) Engineers with less than 36 months of full-time employment. (b) Samples

iren2701 [21]

Answer:

(a) Engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

(c) Measurements of the diameter of forged pistons that conform to engineering specifications.

(d) Cholesterol levels that measure less than 180 and greater than 220.

Step-by-step explanation:

The complement of a set refers to elements that does not exist in that set. It means what does not exist in the set but exist in the universal set.

(a) Engineers with greater than 36 months of full-time employment.

In this case, the Universal set is a set of engineers in full-time employment. The given set is for engineers with less than 36 months of full-time employment. The complement is engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

In this case, the universal set is a set of samples of cement block having compressive strength. The given set is a set of cement block having compressive strength less than 6000 kilograms per square centimeter. The complement is samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter.

(c) Measurements of the diameter of forged pistons that conform to engineering specifications.

In this case, the universal set is a set of measurements of the diameter of forged pistons. The given set is a set of measurements of the diameter of forged pistons that do not conform to engineering specifications. The complement is a set of measurements of the diameter of forged pistons that conforms to engineering specification.

(d) Cholesterol levels that measure less than 180 and greater than 220.

In this case, the universal set is a set of Cholesterol levels. The given set is Cholesterol levels that measure greater than 180 and less than 220. The complement is Cholesterol levels that measure less than 180 and greater than 220.

5 0

1 year ago