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soldi70 [24.7K]
2 years ago
12

A side of a regular six - sided polygon is 8cm long. The perimeter of a similar polygon is 60cm. What is the length of a side of

the larger polygon?​
Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

  10 cm

Step-by-step explanation:

The larger polygon is also a regular 6-sided polygon, so each side is 1/6 of the perimeter length:

  (60 cm)/6 = 10 cm . . . length of a side

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Ruby has a bird feeder which is visited by an average of 13 birds every 2 hours during daylight hours. What is the probability t
zalisa [80]

Answer:

62.93%

Step-by-step explanation:

We have to solve it by a Poisson distribution, where:

p (x = n) = e ^ (- l) * l ^ (x) / x!

Where he would come being the number of birds that there would be in 40 minutes, we know that in 2 hours, that is 120 minutes there are 13, therefore in 40 there would be:

l = 13 * 40/120

l = 4,333

Now, we have p (x> 3) and that is equal to:

p (x> 3) = 1 - p (x <= 3)

So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

p (x = 1) = 2.72 ^ (- 4.33) * 4.33 ^ (1) / 1! = 0.0568

p (x = 2) = 2.72 ^ (- 4.33) * 4.33 ^ (2) / 2! = 0.12310

p (x = 3) = 2.72 ^ (- 4.33) * 4.33 ^ (3) / 3! = 0.17767

If we add each one:

0.01313 + 0.0568 + 0.12310 + 0.17767 = 0.3707

replacing:

p (x> 3) = 1 - 0.3707

p (x> 3) = 0.6293

Which means that the probability is 62.93%

5 0
2 years ago
Choose the correct answer.
Morgarella [4.7K]

Answer: Oh the answer is 30.00

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
You can win concert tickets from a radio station if you are the first person to call when the song of the day is played, or if y
Anit [1.1K]

The song of the day is announced at a random time between 7:00 and 7:30, so you have a 30-minutes span of time where the song could be announced. If you start listening to the radio 20 minutes in, you're at 2/3 of the time. So, there is a 2/3 chance that the song has already been chosen, and a 1/3 chance that it will be announced in the remaining 10 minutes.

Similarly, the trivia question is asked at a random time between 7:15 and 7:45 so there is again a 30-minutes span of time. But this time, we're only 5 minutes late, so there is a 5/30=1/6 chance that the question was already asked, and a 25/30=5/6 chance that the question will be asked in the remaining 25 minutes.

So, there are four scenarios:

  • You have missed both the song of the day and the trivia question. Given all we said, this event has a chance of

\dfrac{2}{3}\cdot\dfrac{1}{6} =\dfrac{2}{18}

  • You miss the song, but not the trivia:

\dfrac{2}{3}\cdot\dfrac{5}{6} =\dfrac{10}{18}

  • You miss the trivia, but not the song

\dfrac{1}{3}\cdot\dfrac{1}{6} =\dfrac{1}{18}

  • You don't miss anything:

\dfrac{1}{3}\cdot\dfrac{5}{6} =\dfrac{5}{18}

You're interested in the probability of missing either of the announcements, so you want to sum the two middle cases (in the first you miss everything, in the second you don't miss anything).

Your result is thus

\dfrac{10}{18}+\dfrac{1}{18} = \dfrac{11}{18}

3 0
2 years ago
What is m∠CDJ ? Enter your answer in the box. ° Line A K and line M J intersect at a right angle at point D. Line L C also passe
Wittaler [7]
I think the answer is 34 tell me if i'm wrong I would love to see my mistakes hope this help plz leave a brainist

3 0
2 years ago
Read 2 more answers
What is the slope of the line tangent to the curve 3y^2-2x^2=6-2xy at the point (3 2)?
MArishka [77]
3y² - 2x² = 6 - 2xy
6ydy/dx - 4x = 0 -2xydy/dx
6ydy/dx+2xydy/dx = 4x
(6y+2xy)dy/dx =4x
dy/dx = 4x/ (6y+2xy)
dy/dx| x=3 : = 4(3) /{ 6(2) +2×3×2}
= 12/ {12+12}
=12/24 = 1/2
5 0
2 years ago
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