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gulaghasi [49]
2 years ago
11

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra

veled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.
Mathematics
1 answer:
alina1380 [7]2 years ago
5 0

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df =  18

At the level of significance ∝ = 0.05 and degree of freedom df =  18

For a right tailed test t, the critical value from the t table is :

t_{0.05, 18} = 1.734

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Answer:202.1

Step-by-step explanation:

Add all the days she worked up (7.5+9.75+6.25) =23.5

Now simply just multiply it with 8.60 and you get your answer

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3 0
1 year ago
Five data entry operators work at the data processing department of the Birmingham Bank. Each day for 30​ days, the number of de
Mice21 [21]

Answer:

Step-by-step explanation:

a)

  • p = Total Number of Defects / Sample Size x Number of Samples
  • 302 / 300 x 30 = 0.0336

  • z = Number of standard deviation = 3
  • σ = Standard deviation of sampling distribution
  • σ = p (1- p) / n = 0.0336 (1- 0.0336) / 300 = 0.0336 x 0.9664 / 300 = 0.0104

  • Here, n = number of observations in each sample

  • UCL = p+zσ = 0.0336 + 3(0.0104) = 0.0336 + 0.0312 = 0.0648 = 0.065

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b) Hence, Lower control limit cannot be a negative number as percent defective cannot be a negative number. As such, No. Percent of defective records cannot be a negative number.

7 0
2 years ago
The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is f(x)=0.0
uysha [10]

Answer:

a) 20%

b) 40%

c) Mean = 62.5 seconds; Variance = 52.083 seconds

Step-by-step explanation:

The time it takes a hematology cell counter to complete a test on a blood sample is continuously distributed over the period of 50 to 75 seconds with probability f(x) = 0.04.

a) The percentage of tests require more than 70 seconds is:

P(X>70) = 1- \frac{70-50}{75-50} \\P(X>70) =0.2 = 20\%

b)The percentage of tests that require less than one minute (60 seconds) is:

P(X70) =0.4 = 40\%

c) The mean and variance of a continuous distribution are determined by:

M=\frac{A+B}{2}=\frac{50+75}{2}\\ M= 62.5\ seconds\\\\V=\frac{(B-A)^2}{12}=\frac{(75-50)^2}{12}\\  V= 52.083\ seconds

Mean = 62.5 seconds.

Variance = 52.083 seconds.

3 0
2 years ago
Charmaine pays $848 for landscaping rocks for a project. The cost per pound is 32 cents. How many pounds did she purchase?
otez555 [7]
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6 0
1 year ago
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This figure shows the nose cone of a rocket used for launching satellites. The nose cone houses the satellite until the satellit
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see the attached figure to better understand the problem

we know that

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the answer is

The volume of the nose cone is 45\pi \ ft^{3}

7 0
1 year ago
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