2 years ago

Find the product of (–d + e)(4e + d). Which statements are true? Check all that apply

2 answers:

6 0

(- d + e)(4e + d)
-d*4e - d^2 + 4e^2 + de
-d^2 - 3de + 4e^2

That's the answer to the expansion. Without choices, there is not much else I can do.

m_a_m_a [10]2 years ago

4 0

Answer:

There are 3 terms in the product.

The product is degree 2.

In other words, B and E. Just got this correct on edge-nuity

Step-by-step explanation:

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In the figure, line L1 is parallel to line L2. If the measure of ∠4 = 144°, what is the measure of ∠6 and why? A. 144°, vertical

Brrunno [24]

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Step-by-step explanation:

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2 years ago

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Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right

Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC² = CA² and AB=BC

ΔABC isosceles right angled triangle.

Step-by-step explanation:

Given vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = $\sqrt{1+1+16} = \sqrt{18}$

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC= $\sqrt{9+9} =\sqrt{18}$

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = $\sqrt{16+4+16} =\sqrt{36} =4$

Since AB²+BC² = CA²

And AB=BC

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2 years ago

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2 years ago

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Step-by-step explanation:

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2 years ago

Factor 16x2 + 121 over the set of complex numbers.<br> Enter your answer in the box.

aliya0001 [1]

Answer:

(4x - 11i)(4x -+11i)

Step-by-step explanation:

Factor as a difference of squares

a² - b² = (a - b)(a + b)

note that i² = - 1

Given

16x² + 121

= (4x)² - (11i)²

= (4x - 11i)(4x + 11i)

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2 years ago