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notka56 [123]
2 years ago
12

Find the product of (–d + e)(4e + d). Which statements are true? Check all that apply

Mathematics
2 answers:
vlada-n [284]2 years ago
6 0
(- d + e)(4e + d)
-d*4e - d^2 + 4e^2 + de
-d^2 - 3de + 4e^2

That's the answer to the expansion. Without choices, there is not much else I can do.
m_a_m_a [10]2 years ago
4 0

Answer:

There are 3 terms in the product.

The product is degree 2.

In other words, B and E. Just got this correct on edge-nuity

Step-by-step explanation:

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Mary bought a paid of jeans and a sweater.The pair of jeans costs $30 and the sweater costs $35 .If sales tax is 6% ,how much di
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In a necklace the ratio of yellow beads to blue beads is 3:1. What percentage of beads are yellow?
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Tanzania [10]

Answer:

Approximately, 159 men weighs more than 165 pounds and  159 men weighs less than 135 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 150 pounds

Standard Deviation, σ = 15

We are given that the distribution of weights of 1000 men is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P( men weighing more than 165 pounds)

P(x > 165)

P( x > 165) = P( z > \displaystyle\frac{165 - 150}{15}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 165) = 1 - 0.8413 = 0.1587 = 15.87\%

Approximately, 159 men weighs more than 165 pounds.

P(men weighing less than 135 pounds)

P(x < 135)

P( x < 135) = P( z < \displaystyle\frac{135 - 150}{15}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 135) = 0.1587 = 15.87\%

Approximately, 159 men weighs less than 135 pounds.

6 0
2 years ago
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