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2 years ago

Find the product of (–d + e)(4e + d). Which statements are true? Check all that apply

2 answers:

6 0

(- d + e)(4e + d)
-d*4e - d^2 + 4e^2 + de
-d^2 - 3de + 4e^2

That's the answer to the expansion. Without choices, there is not much else I can do.

m_a_m_a [10]2 years ago

4 0

Answer:

There are 3 terms in the product.

The product is degree 2.

In other words, B and E. Just got this correct on edge-nuity

Step-by-step explanation:

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How many significant figures in 20340 ?

elena-14-01-66 [18.8K]

There are 4 significant figures in 20340.

7 0

2 years ago

Read 2 more answers

According to the journal Chemical Engineering, an important property of a fiber is its water absorbency. A random sample of 20 p

Feliz [49]

Answer:

Step-by-step explanation:

a )

sample mean = sum total of given data / no of data

= 415.35 / 20 = 20.76

To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .

= 20.50 + 20.72 / 2

= 20.61

b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest

(18.92 + 19.25 ..... + 22.43 + 22.85) / 16

= 20.74

c )

We can easily plot the data on number line from 17 to 24

d )

Maximum value of data set = 23.71 and minimum value is 18.04

mean is 20.76 , median is 20.61 and trimmed mean is 20.74

They are between maximum and minimum values of given data . Hence there is no outliers .

4 0

2 years ago

James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28.

lara31 [8.8K]

Let's use J for James's age and A for Austin's age. The equations are:

J = A - 4
3J + A² = 28

Just plug (A - 4) in the place of J in the second equation. This gives you:

3(A - 4) + A² = 28
-->
A² + 3A - 12 = 28
-->
A² + 3A - 40 = 0
-->
(A - 5)(A + 8) = 0
-->
A = 5 or -8

-8 is nonsense, so Austin is 5 years old. Therefore, James is 1 year old.

7 0

1 year ago

ALGEBRA Jake Duffy drove 12,568 miles

kirza4 [7]

Answer:

The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B

Step-by-step explanation:

Given as :

The distance drove by Jack Duffy = d = 12,568 miles

The fixed costs totaled = $1,485.00

The variable cost totaled = $2,015.75

Let The cost per mile that Jack Duffy charge = $x cost per miles

Now, According to question

The totaled cost = The fixed costs + The variable cost

Or, The totaled cost = $1,485.00 + $2,015.75

I.e The totaled cost = $3500.75

Now,

The cost per mile that Jack Duffy charge = $\dfrac{\extrm Total cost}{\textrm Total Distance}$

I.e x = $\dfrac{3500.75}{12568}$

∴ x = $0.278 per miles

So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .

Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B Answer

5 0

2 years ago

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

2 years ago