Answer:
0.57 or 0.56
Step-by-step explanation:
passenger fares + tax revenue = operating costs
Thus:
passenger fares = operating costs - tax revenue
= $69 million - $30 million
= $39 million
The ratio of passenger fares to total operating costs is:
$39 million
= 0.5652.
$69 million
To the nearest hundredth, the farebox recovery ratio is 0.57.
Answer: She has $1022 left.
Step-by-step explanation:
The total amount that Amee received an the end of year as bonus at work is $1550.
She went on a shopping spree, spending $225 at the department store, $275 at the home furnishing store, and $28 at the card shop. Therefore, the total amount that she spent at the department store, the home furnishing store, and the card shop is
225 + 275 + 28 = $528
Therefore, the total amount of her bonus that she has left is
1550 - 528 = $1022
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15
From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,
0.048 is the probability that more than 950 message arrive in one minute.
