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1 year ago

13

Which graph can be used to find the solution(s) to 4x=-4x?

2 answers:

Elden [556K]1 year ago

6 0

<h2>Answer:</h2>

The graph is shown in the Figure below

<h2>Step-by-step explanation:</h2>

In this exercise, we have an equation. On the left side we have a straight line with slope $m=4$ and there is no any y-intercept. On the right side, on the other had, we also have a straight line, but the slope here is $m=-4$ . Therefore, by plotting these two straight lines, we have that the solution is the origin, that is, the point $(0, 0)$ .

solniwko [45]1 year ago

3 0

Answer:

the graph of f is a line (f is a linear polynomial function) so we can use 2 points to draw it, say (0, 3) and (2, -5)

the graph of g is a parabola (g is a quadratic polynomial function), so we can factorize the expression as follows:

Re

Step-by-step explanation:

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2 years ago

According to Euclid’s second postulate, how far can the line segment shown be extended in either direction?

Vilka [71]

Answer:

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Step-by-step explanation:

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2 years ago

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The table below represents Gerry's trip to school and back home. If the total time is 45 minutes, how far does Gerry live from s

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Step-by-step explanation:

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1 year ago

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The polynomial 10x3 + 35x2 − 4x − 14 is factored by grouping.

vova2212 [387]

Answer: the coomon factor that is missing from both sets of parentheses is 2x + 7.

Explanation:

These are the steps to factor the polynomial with the reasons that justify them:

Step Reason

1. 10x³ + 35x² - 4x - 14 Given

2. (10x³ + 35x²) - (4x + 14) Group the terms

3. 5x² (2x + 7) - 2 (2x + 7) Common factor 5x² and 2

After this, you extract common factor 2x + 7 and have the complete factored polynomial: (2x + 7) (5x² - 2).

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2 years ago

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A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

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2 years ago