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tatyana61 [14]
2 years ago
7

A sumo wrestling ring is circular and has a circumference of 4.6\pi \text{ meters}4.6π meters4, point, 6, pi, start text, space,

m, e, t, e, r, s, end text. What is the area AAA of the sumo wrestling ring in square meters? Give your answer in terms of \piπpi.
Mathematics
1 answer:
Zina [86]2 years ago
7 0

Answer:

The area of the wrestling ring is 5.29π m^2

Step-by-step explanation:

A sumo wrestling ring is circular and has a circumference of 4.6π meters.

To find its area, we need to first find its radius.

The circumference of a circle is given as:

C = 2 \pi r

where r = radius

Hence, the radius of the ring will be:

4.6\pi = 2\pi r\\r = 4.6 /2 = 2.3m

The radius of the ring is 2.3 m.

The area of a circle is given as:

A = \pi r^2

Hence, the area of the wrestling ring (in terms of π) will be:

A = \pi * 2.3^2

A = 5.29\pi m^2

The area of the wrestling ring is 5.29π m^2

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Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

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David:

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Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So X = 52, \mu = 64, \sigma = 6

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2 years ago
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Let's calculate the area of the living/dining room, this way:

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6 0
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