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diamong [38]
2 years ago
6

Write the sum in sigma notation. $ \noindent 1 - x + x^2 - x^3 + \cdot\cdot\cdot + {(-1)}^n x^n $

Mathematics
1 answer:
Neko [114]2 years ago
3 0

1-x+x^2-x^3...+(-1)^nx^n=\sum\limits_{n=0}^{\infty}(-1)^nx^n=\sum\limits_{n=1}^{\infty}(-1)^{n-1}x^{n-1}

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Lorena solved the equation 5k – 3(2k – ) – 9 = 0. Her steps are below. 5k – 6k + 2 – 9 = 0 –k – 7 = 0 –k = 7 k = Analyze Lorena’
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Angle KLM and angle MLN are a linear pair. Ray LR is to be added to the diagram so that it is opposite ray LM. Which is true abo
lesya [120]
Angles RLN and MLK would be vertical angles.
Right. Vertical angles are formed when their sides share the same lines. RL shares the same line with LM and NL shares the same line with LK (see the attached diagram), so that means both angles form a vertical pair.

Angles RLN and MLN would be vertical angles.
Wrong.
They are linear pairs, because they are adjacent and supplementary. Adjacent angles share a side – in this case, LN. Supplementary angles sum 180°, which you can see is right because the other sides (ML and RL) are in the same line. RLN and MLN sum the same as the size of RLM, which is a line, so it’s 180°.  <span>

Angles RLN and KLM would be a linear pair. </span>
Wrong.
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Angles RLN and KLN would be a linear pair.
Wrong.
KLN is actually a line, so it’s actually 180°, so it can’t be a linear pair with KLN. Linear pairs sum 180°, which is impossible because KLN itself is already 180°, so any sum will throw a higher number.



9 0
2 years ago
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Simplify aaa^3bxa^2b^3abx^4
dolphi86 [110]
Aaa^3bxa^2b^3abx^4
=aaa^3a^2abb^3bxx^4
=a^(1+1+3+2+1)b^(1+3+1)x^(1+4)
=a^8^b^5x^5
5 0
2 years ago
How can a translation and reflection be used to map HJK to LMN?
Furkat [3]
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3 0
2 years ago
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A prisoner is trapped in a cell containing three doors. The first door leads to a tunnel that returns him to his cell after two
Greeley [361]

Answer:

The expected number of days until the prisoner reaches freedom is 2.8.

Step-by-step explanation:

Door 1: 0.3 probability of being selected. Leads to his cell after two days' travel.

Door 2: 0.5 probability of being selected. Leads to his cell after four days' travel.

Door 3: 0.2 probability of being selected. Leads to his cell after one day of travel.

What is the expected number of days until the prisoner reaches freedom?

We multiply the probability of each door being used by the time that it leads to the cell. So

E = 0.3*2 + 0.5*4 + 0.2*1 = 2.8

The expected number of days until the prisoner reaches freedom is 2.8.

4 0
2 years ago
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