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jekas [21]
2 years ago
9

The function f(t) represents the cost to connect to the Internet at an online gaming store. It is a function of t, the time in m

inutes spent on the Internet.
f(t) =StartLayout Enlarged left-brace 1st row 1st column 0 dollars 2nd column 0 less-than t less-than-or-equal-to 30 2nd row 1st column 5 dollars 2nd column 30 less-than t less-than-or-equal-to 90 3rd row 1st column 10 dollars 2nd column t greater-than 90 EndLayout

Which statement is true about the Internet connection cost?

It costs $5 per hour to connect to the Internet at the gaming store.
The first half hour is free, and then it costs $5 per minute to connect to the Internet.
It costs $10 for each 90 minutes spent connected to the Internet at the gaming store.
Any amount of time over an hour and a half would cost $10.
Mathematics
2 answers:
dolphi86 [110]2 years ago
3 0

Answer:

<u>The correct answer is D. Any amount of time over an hour and a half would cost $10.</u>

Step-by-step explanation:

f (t), when t is a value between 0 and 30

The cost is US$ 0 for the first 30 minutes

f (t), when t is a value between 30 and 90

The cost is US$ 5 if the connection takes between 30 and 90 minutes

f (t), when t is a value greater than 90

The cost is US$ 10 if the connection takes more than 90 minutes

According to these costs, statements A, B and C are incorrect. The connection doesn't cost US$ 5 per hour like statement A affirms, the cost of the connection isn't US$ 5 per minute after the first 30 minutes free as statement B affirms and neither it costs US$ 10 for every 90 minutes of connection, as statement C affirms. <u>The only one that is correct is D, because any amount of time greater than 90 minutes actually costs US$ 10.</u>

irinina [24]2 years ago
3 0

Answer:

The correct answer is D. Any amount of time over an hour and a half would cost $10.

Step-by-step explanation:

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During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60÷5 60 ÷ 5 in this context. Fi
Afina-wow [57]

The second question:

Consider the division expression 7\frac{1}{2} / 2. Select all multiplication equations that correspond to this division expression.

2 * ? = 7\frac{1}{2}     7\frac{1}{2} * ?= 2     ? * 2  = 7\frac{1}{2}

2* 7\frac{1}{2} = ?    ?  * 7\frac{1}{2} = 2

Answer:

1. See Explanation

2. 2 * ? = 7\frac{1}{2}     and     ? * 2  = 7\frac{1}{2}

Step-by-step explanation:

Solving (a):

Given

Students = 60

Group = Equal\ Sized

Required

Interpret \frac{60}{5} in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

Quotient = \frac{60}{5}

Quotient = 12

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

7\frac{1}{2} / 2

Required

Select all equivalent multiplication equations

Let ? be the quotient of t 7\frac{1}{2} / 2

So, we have:

7\frac{1}{2}/2 = ?

Multiply through by 2

2 * 7\frac{1}{2}/2 = ? * 2

7\frac{1}{2} = ? * 2

Rewrite as:

? * 2 = 7\frac{1}{2}  --- This is 1 equivalent expression

Apply commutative law of addition:

2 * ? = 7\frac{1}{2}  --- This is another equivalent expression

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pantera1 [17]

Answer: 20%

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4 0
2 years ago
Consider △RST and △RYX. If the triangles are similar, which must be true? A. RY/YS=RX/XT=XY/TS B.RY/RS=RX/RT=XY/TS C.RY/RS=RX/RT
trasher [3.6K]

Answer:

B.RY/RS=RX/RT=XY/TS

Step-by-step explanation:

If Triangles RST and RYX are similar, then the ratio of their corresponding sides is:

\dfrac{RS}{RY}= \dfrac{ST}{YX}=\dfrac{RT}{RX}\\$This could also be written by switching the numerator and denominators as:\\\dfrac{RY}{RS}= \dfrac{XY}{TS}=\dfrac{RX}{RT}

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3 0
2 years ago
Two containers, X and Y, are each filled by an ideal gas at the same temperature. The volume of Y is half the volume of X. The n
-Dominant- [34]

Answer:

The answer to the question is

The ratio of the two gas pressures   \frac{P_{x} }{P_{y} } , that is Px to Py = 1/6

Step-by-step explanation:

Let the gases Volumes be V₁ and V₂

Where volume of X = V₁ and

volume of Y = V₂

The volume of Y is half the volume of X

∴ V₂  =  \frac{1}{2} × V₁

Let the number of moles be n₁ and n₂ in X and Y respectively

therefore  n₂ = 3 × n₁

The pressure of the gas in X is Pₓ and the pressure of the gas in Y is  P_{y} then we have

P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂

(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)

but T₁ = T₂

Therefore

(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =  \frac{1}{2} × V₁ therefore substituting in the equation we have

(P₁ × V₁)/n₁ = (P₂ ×  \frac{1}{2} × V₁ )/(3 × n₁) from where

P₁ /P₂ =  (\frac{1}{2} × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6

The ratio of \frac{P_{x} }{P_{y} } = 1/6

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2 years ago
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