Ask question

Ask question

All categories

1 year ago

15

What are equivalent equations? How do you find them? Write a few sentences describing them.

2 answers:

lbvjy [14]1 year ago

5 0

Equivalent equations are equations that have exactly the same solution. To find equivalent equations, it is best to solve them individually to find the solutions. The ones with the same solution in the end are considered equivalent equations.

Hope this helps!

d1i1m1o1n [39]1 year ago

3 0

Answer:

Equivalent equations are equations that have exactly the same solution. To find equivalent equations, it is best to solve them individually to find the solutions. The ones with the same solution in the end are considered equivalent equations.

Step-by-step explanation:

You might be interested in

A hungry college student just finished eating a large cheese and pepperoni pizza from Doug's Pizza Palace and felt there wasn'

maw [93]

Answer: 14

Step-by-step explanation:

Degrees of freedom is the number of values in the evaluation of a test statistic that are free to vary.

For t-statistic , the degree of freedom for a sample with sample size 'n' is given by :-

$df=n-1$

Given : Sample size : n-1

Then, the number of degrees of freedom the t-value will have :-

$df=15-1=14$

Hence, the t-value will have 14 degrees of freedom.

7 0

2 years ago

Maya shaved her head and then began letting her hair grow.

Brums [2.3K]

Answer:

Maya grows hair

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The number 31 is increased to 44. What is the percentage by which the number was increased, to the nearest tenth of a percent?

Sophie [7]

Answer:

41.9 %

Step-by-step explanation:

when you look at the to numbers you will see that the two has a 41.9 % difference.

3 0

1 year ago

containers a and b hold 11,875 L of water together. conatainer b holds 2,391L more than container B holds. How many Liters of wa

Licemer1 [7]

Step 1 : 11875=2x+2391 Step 2: 11875-2391=2x Step 3: 9484=2x Step 4: 9484/2=x Step 5: x=4742

4 0

1 year ago

A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80

miskamm [114]

Answer:

$\epsilon = 3.958\times 10^{-3}$

Step-by-step explanation:

The Young's Module of Aluminium is $E = 69\times 10^{9}\,Pa$ . The axial stress on the specimen is:

$\sigma = \frac{F}{A_{t}}$

$\sigma = \frac{35500\,N}{(0.01\,m)\cdot (0.013\,m)}$

$\sigma = 2.731\times 10^{8}\,Pa$

The strain is derived of following expression:

$\epsilon = \frac{\sigma}{E}$

$\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}$

$\epsilon = 3.958\times 10^{-3}$

4 0

2 years ago