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devlian [24]
2 years ago
6

Maya shaved her head and then began letting her hair grow.

Mathematics
2 answers:
Brums [2.3K]2 years ago
6 0

Answer:

Maya grows hair

Step-by-step explanation:

Alexxandr [17]2 years ago
3 0

Answer:Maya will not be bald anymore.

Step-by-step explanation:

Her hair is growing. sCiEnCe

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
William works at a nearby electronics store. He makes a commission of 6\%6%6, percent on everything he sells. If he sells a comp
pentagon [3]
If the computer sells for $764 and commission is 6%, then he would make $45.84 off that sale.
 
764*.06=45.84

Hope this helps :)
8 0
2 years ago
Read 2 more answers
Rectangle ABCD was dilated to create rectangle A'B'C'D' using point R as the center of dilation.
Slav-nsk [51]

Answer:

5

Step-by-step explanation:


8 0
2 years ago
Read 2 more answers
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm?
ololo11 [35]

central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians

Step-by-step explanation:

We need to find the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm.

arc length l== 7.2 cm

radius =r= 8 cm

central angle=Ф = ?

The formula used is:

l=r\theta

Putting values:

\theta=\frac{l}{r}\\ \theta=\frac{7.2}{8} \\\theta=0.9\,\,radians

So, central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians

Keywords: central angle of circle

Learn more about central angle of circle at

  • brainly.com/question/8618791
  • brainly.com/question/1952668
  • brainly.com/question/2860697

#learnwithBrainly

4 0
2 years ago
Harry's Electronics kept track of how many customers bought a newly released gaming system during the first month it was availab
lukranit [14]
More description not a valid question.
6 0
2 years ago
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