The population P of a small island was 6380 , correct to the nearest 10.

You are in a bike race. When you get to the first checkpoint, you are 25 of the distance to the second checkpoint. When you get

Rom4ik [11]

Question:

You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?

Answer: 4 miles

Step-by-step explanation:

Let distance between start to first checkpoint = x

First checkpoint to second checkpoint = 2/5 of x

Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)

Distance of start to checkpoint 2 = (1/4 of start to finish)

If start to checkpoint 2 = 1/4 of start to finish

Then,

Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)

Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish

Entire race = 40 miles = distance from start to finish

1/ 10 of 40

= ( 1/10) × 40

= 4 miles

6 0

2 years ago

Dwayne earns $11.45 per hour.Last week he worked 38 1/4 hours.how much did he earn last week?

Tcecarenko [31]

Answer:

$2,000

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un

Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, assuming a significance level 0.1

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

$H_{0}:$ p1=p2

$H_{a}:$ p1≠p2

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }$ where

p1 is the sample proportion of West University students who involved in a car accident within the past year (0.15)
p2 is the sample proportion of East University students who involved in a car accident within the past year (0.12)

p is the pool proportion of p1 and p2 ( $\frac{15+12}{100+100}=0.135$ )
n1 is the sample size of the students from West University (100)
n2 is the sample size ofthe students from East University (100)

Then we have z= $\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } }$ ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

Assuming significance level 0.1, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0

1 year ago

If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs

sammy [17]

Answer:

$QS=68\ units$