The population P of a small island was 6380 , correct to the nearest 10.

A 700 g dry fruit pack costs ₹216 .It contains some almonds and the rest cashew kernel.If almonds cost ₹288 per kg and cashew ke

slamgirl [31]

Answer:

Almonds = 400grams

Cashew = 300 grams

Step-by-step explanation:

Let the grams of cashew be represented by = C

the grams of almonds be represented by = A

A 700 g dry fruit pack costs ₹216 .It contains some almonds and the rest cashew kernel

C + A = 700g ......Equation 1

C = 700 - A

If almonds cost ₹288 per kg and cashew kernel cost ₹336 per kg

Let's convert them to grams

1 kg = 1000grams

For almonds

= 288/1000 = 0.288g

For cashew

= 336/1000 = 0.336g

Hence,

0.288 × A + 0.336g × C = ₹216

0.288A + 0.336C = 216

From Equation 1, substitute 700 - A for C in Equation 2

0.288A + 0.336(700 - A) = 216

0.288A + 235.2 - 0.336A = 216

Collect like terms

0.288A - 0.336A = 216 - 235.2

- 0.048A = -19.2

A = -19.2/-0.048

A = 400 grams

Substitute 400g for a in Equation 1

C + A = 700g ......Equation 1

= C + 400g = 700g

C = 700g - 400g

C = 300g

Therefore, the number of grams of Almonds = 400grams

Cashew = 300 grams

6 0

2 years ago

What is the place value of 3 in 9. 365?

nikdorinn [45]

Answer:

It is in the tenths place

Step-by-step explanation:

In the number 9.365, 3 is in the tenths place.

8 0

1 year ago

Read 2 more answers

There are 11 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with

BigorU [14]

Step-by-step explanation:

a) 7!

If there are no restrictions, answer is 7! as it is the permutation of all animals.

b) 4! x 3!

As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among themselves and the order of the dogs among themselves. There are 4! permutations of the cats and 3! permutations of the dogs, so there are a total of 4! x 3! possible arrangements of the suites.

c) 3! x 5!

There are 3! possible arrangements of the dogs among themselves. Now, if we consider the dogs as one ”object” together, then we can think of arranging the 4 cats together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.

d) 2 x 4! x 3!

As required that all the cats must be together and all the dogs must be together, either the cats are all before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e. 2 x 4! x 3!

3 0

2 years ago

Write the decimal 1,072.039 in words

Rina8888 [55]

One thousand seventy two point thirty nine thousandths.

3 0

2 years ago

Write an absolute value equation to satisfy the given solution set shown on a number line.

aivan3 [116]

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.

8 0

2 years ago