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aleksandrvk [35]
1 year ago
9

A hair stylist knows that 87% of her customers get a haircut and 40% get their hair colored on a regular basis. Of the customers

who get their hair cut, 24% also get their hair colored. What is the probability that a randomly selected customer gets their hair cut and colored?
0.10
0.21
0.35
0.40
Mathematics
1 answer:
kvv77 [185]1 year ago
7 0

Answer:

Okay so!

Step-by-step explanation:

for a cut that's .87 and for a color that is .24 so you multiply them together to get the probability for the color which is

.35 or C on edge

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What is the axis of symmetry of h(x) = –2x2 + 12x – 3?
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h(x) = -2x2 + 12x - 3?

The axis of symmetry is :

x = 3

Hope this helps.

Welcome to Brainly!,

Davinia.

8 0
2 years ago
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Peter Johnson, the CFO of Homer Industries, Inc is trying to determine the Weighted Cost of Capital (WACC) based on two differen
Rzqust [24]

Answer:

Scenario 1 has WACC of 7.93%

Scenario 2 has WACC of 10.33%

Step-by-step explanation:

WACC=Ke*E/V+Kp*P/V+Kd(after tax)*D/V

Ke is the cost of equity =13%

Kp is the cost of preferred stock=10%

Kd(after tax) is the cost of debt of 8% adjusted for tax as below:

Kd(after tax )=Kd(before tax)*(1-t)

t is the tax rate of 30% or 0.3

Kd(after tax)=8%*(1-0.3)=5.60%

E is equity value,which is $1.8 million under scenario 1 and $3.8 under scenario 2

P is the value of preferred stock which is $1.2 million and $2.2 million respectively

D is the value of debt which is $5 million and $2 million

V=total value of capital structure=$8 million in both cases.

Scenario 1 WACC

WACC=13%*1.8/8+10%*1.2/8+5.6%*5/8=7.93%

Scenario 2 WACC

WACC=13%*3.8/8+10%*2.2/8+5.6%*2/8=10.33%

7 0
1 year ago
Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch
enot [183]

Answer:

y=\frac{-7t^2+22t-7}{7t-22}

Step-by-step explanation:

We are given that

Initial value problem

y'=(t+y)^2-1, y(3)=4

Substitute the value z=t+y

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z=3+4=7

y'=z^2-1

Differentiate z w.r.t t

Then, we get

\frac{dz}{dt}=1+y'

z'=1+z^2-1=z^2

z^{-2}dz=dt

Integrate on both sides

-\frac{1}{z}dz=t+C

z=-\frac{1}{t+C}

Substitute t=3 and z=7

Then, we get

7=-\frac{1}{3+C}

21+7C=-1

7C=-1-21=-22

C=-\frac{22}{7}

Substitute the value of C then we get

z=-\frac{1}{t-\frac{22}{7}}

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y=z-t

y=\frac{-7}{7t-22}-t

y=\frac{-7-7t^2+22t}{7t-22}

y=\frac{-7t^2+22t-7}{7t-22}

8 0
2 years ago
Dalia flies an ultralight plane with a tailwind to a nearby town in 1/3 of an hour. On the return trip, she travels the same dis
pashok25 [27]
Dalia had an average airspeed of ⇒ 42 miles per hour.
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8 0
2 years ago
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Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can
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Answer:

The answer is 3√5 mi.

The formula is: d = √(3h/2)

Wyatt:

h = 120 ft

d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?

Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi

3 0
2 years ago
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