Answer:
0.0045 = 0.45% probability that less than two of them ended in a divorce
Step-by-step explanation:
For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
55% of marriages in the state of California end in divorce within the first 15 years.
This means that 
Suppose 10 marriages are randomly selected.
This means that 
What is the probability that less than two of them ended in a divorce?
This is

In which




0.0045 = 0.45% probability that less than two of them ended in a divorce
The correct answer for the question that is being presented above is this one: "D.)11.24 m2."
First, we need to know the conversion between feet to meters.
1 meter = 3.28 feet
1 meter^2 = 10.7584 ft^2
Given the value of 121 ft^2,
= 121 ft^2 * (1 m^2 / 10.7584 ft^2)
= 11.2470 m^2
Answer:
which one do you need help on
Answer:
Step-by-step explanation:
For the null hypothesis,
H0 : p = 0.63
For the alternative hypothesis,
Ha : p < 0.63
This is a left tailed test
Considering the population proportion, probability of success, p = 0.63
q = probability of failure = 1 - p
q = 1 - 0.63 = 0.37
Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 478
n = number of samples = 800
P = 478/800 = 0.6
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76
From the normal distribution table, the area below the test z score in the left tail 0.039
Thus
p = 0.039