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1 year ago

Given f(x) = x3 – 2x2 – x + 2, the roots of f(x) are

Mathematics

2 answers:

ANTONII [103]1 year ago

8 0

Answer:

Question 1: -1, 1, 2

Question 2: B

Question 3: 1, 2, below

Step-by-step explanation:

kolezko [41]1 year ago

3 0

You have the following expression given in the problem:

f(x) = x³ – 2x²<span> – x + 2

Therefore, to find the roots, you must apply the proccedure shown below:

1. You have:

0 </span><span>= x3 – 2x2 – x + 2

2. Then, when you factor, you obtain:

(x-2)(x-1)(x+1)=0

3. Therefore, you have that the roots are the following:

x1=-1
x2=1
x3=2</span>

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2 years ago

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Lostsunrise [7]

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2 years ago

Find the value of the linear correlation coefficient r. The paired data below consist of the temperatures on randomly chosen day

n200080 [17]

Answer:

n=9 $\sum x = 530, \sum y = 243, \sum xy = 14615, \sum x^2 =32656, \sum y^2 =8245$

And replacing the info we got:

$r=\frac{9(14615)-(530)(243)}{\sqrt{[9(32656) -(530)^2][9(8245) -(243)^2]}}=0.1955$

So then the correlation coefficient would be r =0.1955

Step-by-step explanation:

Data given

Temperature (x) 62 76 50 51 71 46 51 44 79

Growth (y) 36 39 50 13 33 33 17 6 16

Solution

The correlation formula is given by:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have the following sums:

n=9 $\sum x = 530, \sum y = 243, \sum xy = 14615, \sum x^2 =32656, \sum y^2 =8245$

And replacing the info we got:

$r=\frac{9(14615)-(530)(243)}{\sqrt{[9(32656) -(530)^2][9(8245) -(243)^2]}}=0.1955$

So then the correlation coefficient would be r =0.1955

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1 year ago

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