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tamaranim1 [39]
1 year ago
13

Roger has 4 gallóns of orange juice. He puts the same amount of juice each of 5 pitchers. How many gallons of orange juice are i

n 1 pitcher?​
Mathematics
1 answer:
salantis [7]1 year ago
5 0

Answer:

1.25

Step-by-step explanation:

you divide 5 within 4 to get how much Roger puts on each pitch

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What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2Plus or minus 2 StartRoot 5 EndRoot x = ±6Plus or minus 6
Serga [27]

Question:

What are the solution(s) to the quadratic equation 50 – x2 = 0?

A) x = ±2Plus or minus 2 StartRoot 5 EndRoot

B) x = ±6Plus or minus 6 StartRoot 3 EndRoot

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

D) no real solution

Answer:

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

3 0
1 year ago
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Which statement identifies how to show that j(x) = 11.6ex and k(x) = In (StartFraction x Over 11.6 EndFraction) are inverse func
Vadim26 [7]

Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

For j(k(x));

j(k(x)) = j[(ln x/11.6)]

j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}

j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)

j[(ln x/11.6)] = 11.6 * x/11.6

j[(ln x/11.6)] = x

Hence j[k(x)] = x

Similarly for k[j(x)];

k[j(x)] = k[11.6e^x]

k[11.6e^x] = ln (11.6e^x/11.6)

k[11.6e^x]  = ln(e^x)

exponential function will cancel out the natural logarithm leaving x

k[11.6e^x]  = x

Hence k[j(x)] = x

From the calculations above, it can be seen that j[k(x)] =  k[j(x)]  = x, this shows that the functions j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6} are inverse functions.

4 0
1 year ago
Circle O has a circumference of approximately 250π ft. Circle O with diameter d is shown. What is the approximate length of the
Vinil7 [7]

Answer:

250 ft

Step-by-step explanation:

circumference of circle 'C' is defined as

C = 2πr

250π = 2πr

r = 250π/2π

r= 125

d = 2r = 2×125 = 250 .

diameter of the given circle is 250 ft

4 0
1 year ago
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The dot plots below show rainfall totals in the Highlands and Lowlands areas of a certain region.
Andre45 [30]

Options:

A. Both the Highlands and the Lowlands data points are evenly distributed around the center.

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

C. The Highlands data points are evenly distributed around the center, while the Lowlands data points are clustered toward the left of the plot.

D. The Highlands data points are clustered toward the left of the plot, while the Lowlands data points are evenly distributed.

Answer:

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

Step-by-step Explanation:

From the dot plots displaying rainfall totals for highland and lowland areas as shown in the diagram attached below, we can clearly observe that most of the dots on the plot tend to be more concentrated towards the left of the plot, compared to the concentration of dots toward the right of the plot.

Invariably, we can infer that data points for lowlands and Highlands are clustered toward the left of the plot.

Therefore, the statement that is true, comparing the shapes of the dot plot is B. "Both the Highlands and the Lowlands data points are clustered toward the left of the plot."

7 0
1 year ago
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VladimirAG [237]
Can you send the answer choices?
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