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Liula [17]
1 year ago
10

A grocer has 2 types of tea, one for sells for $8.00 per pound and the other for $6.00. How many pounds of each kind must he use

to make 50 pounds of tea that will sell for $7.40 per pound
Mathematics
1 answer:
fiasKO [112]1 year ago
6 0
Equation::
value + value = value
80x + 60(50-x) = 74*50
----
80x + 60*50 - 60x = 74*50
----
20x = 14*50
x = 35 lbs (amt. of 80 cent tea to use)
50-x = 15 lbs (amt. of 60 cent tean to use)
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To add the jumps made by three frogs, you have to convert the units into a specific unit for uniformity. Let us use meter. For every 1 meter, there are 100 centimeter and 1000 millimeters. Divide 85 by 100 and 400 by 1000.

 

<span>1 + 85/100 + 400/1000 = 2.25 meters</span>

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List at least three (3) characteristics of carbon that make it a unique element.
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1.) Carbon Compounds are the backbone of all organic compounds that are the basic building blocks of all living things.

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2 years ago
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The hypotenuse of a 45 -45° -90° triangle measures 18 cm. What is the length of one leg of the triangle?
sdas [7]
<h2>Steps</h2>

So the 45-45-90 triangle is considered to be a "special triangle" and has a rule with it. If the legs are x, then the hypotenuse is x√2. Since we know that the hypotenuse is 18, this means we can set up our equation as such:

x\sqrt{2} =18

From here we can solve for x. Firstly, divide both sides by √2.

x=\frac{18}{\sqrt{2}}

Next, we want to simplify this expression and to do that we first have to rationalize the denominator. With the right side, multiply the numerator and denominator by √2:

\frac{18}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}=\frac{18\sqrt{2}}{2}\\\\\\x=\frac{18\sqrt{2}}{2}

Next, divide:

x=9\sqrt{2}

<h2>Answer</h2>

<u>In short, the length of one leg of the triangle is 9√2 cm.</u>

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In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

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Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

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1 year ago
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