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2 years ago

The speed of light is 3 x 108 m/s. If its frequency is 4.11 x 104 Hz, what is its wavelength?

Mathematics

1 answer:

QveST [7]2 years ago

5 0

Answer:

Wave length = speed / frequency

Wave length = 3x10^8 / 4.11x10^4

Wave length = 7.299x10^3nm

Step-by-step explanation:

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Calculate a23 for the product of the following matrices

s344n2d4d5 [400]

If $A$ is the matrix product

$A=\underbrace{\begin{pmatrix}1&2\\4&3\end{pmatrix}}_{M_1}\underbrace{\begin{pmatrix}6&1&5\\7&3&4\end{pmatrix}}_{M_2}$

and $a_{2,3}$ is the entry of $A$ in the second row and third column, then

$a_{2,3}=\begin{pmatrix}4&3\end{pmatrix}\begin{pmatrix}5\\4\end{pmatrix}=4\times5+3\times4=\boxed{32}$

That is, the 2nd row, 3rd column entry of $A$ is the product of the 2nd row of $M_1$ and the 3rd column of $M_2$ .

6 0

1 year ago

a basketball player made 27 free throws in her last 45 tries. what is the experimental probability that she will make her next f

Strike441 [17]

Hey mark me brainlest but ur answer is 27/45

Bess ur day.

8 0

1 year ago

The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca

dem82 [27]

Answer:

$\frac{4}{663}$

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

A - the first card is 4

B - second card is ace

We have to find probability for

$A\bigcap B$

P(A) = no of 4s in the deck/total cards = $\frac{4}{52} =\frac{1}{13}$

After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it

P(B) = no of Aces in 51 cards/51 = $\frac{4}{51}$

Hence

$P(A\bigcap B) = \frac{1}{13} *\frac{4}{51} \\=\frac{4}{663}$

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)

8 0

1 year ago

Read 2 more answers

Alchen [17]

Answer: C)27:1

Step-by-step explanation:

Given, Kent has two similar cylindrical pipes, Pipe A and Pipe B. The radius of Pipe A is 6 cm, and the radius of Pipe B is 2 cm.

Volume of cylinder = $\pi r^2h$ , where r= radius and h = height.

Also, If two figures are similar then ratio of volume is equal to the cube of any dimension .

The ratio of the volume of Pipe A to the volume of Pipe B is given by :-

$\dfrac{\text{Volume of pipe A}}{\text{Volume of pipe B}}=\dfrac{6^3}{2^3}\\\\=\dfrac{216}{8}=\dfrac{27}{1}$

Thus, the ratio of the volume of Pipe A to the volume of Pipe B = 27:1

So, the correct option is C)27:1.

7 0

1 year ago

Given a rectangular pyramid and a rectangular prism that have the same base and same height, how do their volumes compare? If th

Luden [163]

We know that
volume of a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height

volume of a rectangular pyramid=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

the answer part a) is
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

Part b) If the pyramid was full of water, how much of the prism would it fill up?

the answer part b) is
If the pyramid was filled with water, the prism would only fill 1/3 of its volume

Part c) Name another pair of three-dimensional objects that have a relationship similar to this

cones and cylinders

volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height 

volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder

4 0

1 year ago