Answer: 14.97 per pair of earrings
Step-by-step explanation:
1/2 of the cake was eaten
1+2=3. 3/6=1/2
All the slices are the same size
285 - 60x ; where x represents the number of driving hours.
285 ⇒ <span>The total distance to the state park.
60x </span>⇒<span> </span><span>The number of miles driven after x hours.
60 </span>⇒<span> </span><span>The number of miles driven after 1 hour.
y = 285 - 6x
y </span>⇒<span> </span><span>The number of miles left to drive each day.</span>
Answer:
- The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.
- The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.
Step-by-step explanation:
a) How much will you have at the middle of the first year?
Using the formula

where
Given:
Principle P = $300
Annual rate r = 6% = 0.06 per year
Compound n = Semi-Annually = 2
Time (t in years) = 0.5 years
To determine:
Total amount = A = ?
Using the formula

substituting the values



$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.
Part b) How much at the end of one year?
Using the formula

where
Given:
Principle P = $300
Annual rate r = 6% = 0.06 per year
Compound n = Semi-Annually = 2
Time (t in years) = 1 years
To determine:
Total amount = A = ?
so using the formula

so substituting the values


$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.
Answer:
Distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.
Step-by-step explanation:
Let the distance from Mason's house to Chloe's house is x times as great as the distance from Mason's to Kevin's house.
Distance from Mason's house to Kevin's house=
inches.
Distance from Mason's house to Chloe's house =
inches
ATQ

So, distance from Mason's house to Chloe's house is 160 times as great as the distance from Mason's to Kevin's house.
Hence distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.