The distance from Mason's house to Kevin's house is about 5 × 105 inches. The distance from Mason's house to Chloe's house is ab
1 answer:
Answer:
Distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.
Step-by-step explanation:
Let the distance from Mason's house to Chloe's house is x times as great as the distance from Mason's to Kevin's house.
Distance from Mason's house to Kevin's house= inches.
Distance from Mason's house to Chloe's house = inches
ATQ
So, distance from Mason's house to Chloe's house is 160 times as great as the distance from Mason's to Kevin's house.
Hence distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.
You might be interested in
Answer: see the graphic
Step-by-step explanation:
A. Type I error helps us to conclude that the flight is not profitable, when in fact it is profitable.
B. a = 0.05
C. Type II error does not show that the flight is profitable
Answer:
a
The 95% confidence interval is
b
The sample proportion is
c
The critical value is
d
The standard error is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of defective is k = 18
The null hypothesis is
The alternative hypothesis is
Generally the sample proportion is mathematically evaluated as
Given that the confidence level is 95% then the level of significance is mathematically evaluated as
Next we obtain the critical value of from the normal distribution table, the value is
Generally the standard of error is mathematically represented as
substituting values
The margin of error is
=>
=>
The 95% confidence interval is mathematically represented as
=>
=>
Euler's formula tells us that
Suppose we subtract the two. This eliminates the cosine terms.
Divide both sides by
and you're done.
Suppose we subtract the two. This eliminates the cosine terms.
Divide both sides by