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Fofino [41]
1 year ago
6

The random variable X is exponentially distributed, where X represents the waiting time to see a shooting star during a meteor s

hower. If X has an average value of 75 seconds, what are the parameters of the exponential distribution?
Mathematics
1 answer:
faltersainse [42]1 year ago
3 0

Answer:

The parameters of the exponential distribution is 0.0133.

Step-by-step explanation:

Exponential distribution is a continuous probability distribution.

The density function of exponential distribution is,  

f _{X}(x)=\theta \cdot e^{-\theta\cdot x},\ x\geq 0

Here the parameter θ is the reciprocal of the mean of the random variable <em>X</em>.

The random variable <em>X</em> has an average value of 75 seconds.

Compute the parameters of the exponential distribution as follows:

\theta=\frac{1}{\mu}\\\\

  =\frac{1}{75}\\\\=0.013333333333\\\\\approx 0.0133

Thus, the parameters of the exponential distribution is 0.0133.

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There were 4 ducks living in Anoop's pond when he first built it.

Step-by-step explanation:

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The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo
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Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

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2 years ago
Ann's car can travel 228 miles on 6 gallons of gas. a. Write an equation to represent the distance, y, in miles Ann's car can tr
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Step-by-step explanation:

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1 year ago
An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equ
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Answer:

0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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\mu = 800, \sigma = 40, n = 16, s = \frac{40}{\sqrt{16}} = 10

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This probability is the pvalue of Z when X = 775. So

Z = \frac{X - \mu}{s}

Z = \frac{775 - 800}{10}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062. So there is a 0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

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