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nasty-shy [4]
1 year ago
10

You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In

two months, each of you had made $224. How much profit did the shop make in the second month?
Mathematics
1 answer:
ludmilkaskok [199]1 year ago
7 0
Hello! I can help you with this! So, you and 3 friends are 4 people. You split $536. To find the amount each of you got, Do division. 536/4 is 134. Each friend got $134 in the first month. You made 224 in 2 months. Let’s subtract to see how much more each of them got. 224 - 134 is 90. Now, multiply by 4 to find out how much profit was made. 90 * 4 is 360. The shop made $360 in the second month.
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Answer: a) \frac{24}{5}t gallons are needed to travel 8 miles

b) Town X and town Y are 15 miles apart.

Step-by-step explanation:

Given : Gasoline used to travel 5 miles = 3t gallons

a) To find: Gasoline used to travel 8 miles = ?

Using unitary method:

If Gasoline used to travel 5 miles = 3t gallons

Thus Gasoline used to travel 8 miles = \frac{3t}{5}\times 8=\frac{24}{5}t gallons

\frac{24}{5}t gallons are needed to travel 8 miles

b) when 3t gallons of gasoline are used , distance covered = 5 miles

Thus when 9t gallons of gasoline are used , distance covered = \frac{5}{3t}\times 9t=15 miles

Thus town X and town Y are 15 miles apart.

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2 years ago
Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot
Anastasy [175]

Option B : \frac{1}{\sqrt[3]{x^{5} } } is the expression equivalent to x^{-\frac{5}{3}

Explanation:

The given expression is x^{-\frac{5}{3}

Rewriting the expression x^{-\frac{5}{3} using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

\frac{1}{x^{\frac{5}{3} } }

Simplifying, we get,

\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}

Applying the rule, a^{\frac{1}{n}}=\sqrt[n]{a}

Thus, we have,

\frac{1}{\sqrt[3]{x^{5} } }

Now, we shall determine from the options that which expression is equivalent to x^{-\frac{5}{3}

Option A: \frac{1}{\sqrt[5]{x^{3} } }

The expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to x^{-\frac{5}{3}

Hence, Option A is not the correct answer.

Option B: \frac{1}{\sqrt[3]{x^{5} } }

The expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to the simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to x^{-\frac{5}{3}

Hence, Option B is the correct answer.

Option C: -\sqrt[3]{x^5}

The expression -\sqrt[3]{x^5} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[3]{x^5} is not equivalent to x^{-\frac{5}{3}

Hence, Option C is not the correct answer.

Option D: -\sqrt[5]{x^3}

The expression -\sqrt[5]{x^3} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[5]{x^3} is not equivalent to x^{-\frac{5}{3}

Hence, Option D is not the correct answer.

4 0
2 years ago
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Answer:

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Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

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t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

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dsp73

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Step-by-step explanation:

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P(A and B)= 0.14 + 0.31 - 0.14=0.31

Hence, the required probability : 0.31

7 0
2 years ago
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Answer:

c is the answer

Step-by-step explanation:

hope it is correct tho

8 0
1 year ago
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