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Blizzard [7]
1 year ago
5

Lines m and n are cut by transversal l. Lines m and n are cut by transversal l. On line m where it intersects line l, 4 angles a

re created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line n where it intersects line l, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7. Which angle relationships are correct? Check all that apply. ∠1 and ∠8 are alternate exterior angles. ∠4 and ∠6 are same side interior angles. ∠5 and ∠7 are vertical angles. ∠2 and ∠8 are corresponding angles. ∠3 and ∠6 are alternate interior angles.
Mathematics
2 answers:
Semmy [17]1 year ago
5 0

∠1 and ∠8 are alternate exterior angles and ∠3 and ∠6 are alternate interior angles

step-by-step explanation:

When the transversal crosses line m and n, alternate angles are the pair of angles formed on the outside of each of the lines and opposite side of the transversal (∠1 and ∠8). However,alternate interior angles will form opposite of the transversal but inside the lines.(∠3 and ∠6 ).

Learn More

brainly.com/question/12441758

Keywords : Transversal, angles

#LearnwithBrainly

Bogdan [553]1 year ago
5 0

Answer:

a, b, e

Step-by-step explanation:

got it right on edge

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<h2>Answer:</h2>

→ Friction resists motion

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<h2>Explanation:</h2>

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Answer:

Step-by-step explanation:

If the exchange rate between British pounds (£) and US dollars ($) is £1 = $1.40, how much is £200 worth in dollars?

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Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 6.7 per year. a. Find t
igor_vitrenko [27]

Answer:

a) 10.34% probability​ that, in a​ year, there will be 4 hurricanes.

b) 3.62 years are expected to have 4 ​hurricanes

c) Either 3 or 4 hurricanes(discrete number) are close to the mean of 3.62, which means that the Poisson distribution works well in this case.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

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This means that \mu = 6.7

a. Find the probability​ that, in a​ year, there will be 4 hurricanes.

This is P(X = 4).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-6.7}*(6.7)^{4}}{(4)!} = 0.1034

10.34% probability​ that, in a​ year, there will be 4 hurricanes.

b. In a 35​-year ​period, how many years are expected to have 4 ​hurricanes?

Each year, 0.1034 probability of 10 hurricanes.

In 35 years

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c. How does the result from part​ (b) compare to a recent period of 35 years in which 3 years had 4 ​hurricanes? Does the Poisson distribution work well​ here?

Either 3 or 4 hurricanes(discrete number) are close to the mean of 3.62, which means that the Poisson distribution works well in this case.

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