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Blizzard [7]
2 years ago
5

Lines m and n are cut by transversal l. Lines m and n are cut by transversal l. On line m where it intersects line l, 4 angles a

re created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line n where it intersects line l, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7. Which angle relationships are correct? Check all that apply. ∠1 and ∠8 are alternate exterior angles. ∠4 and ∠6 are same side interior angles. ∠5 and ∠7 are vertical angles. ∠2 and ∠8 are corresponding angles. ∠3 and ∠6 are alternate interior angles.
Mathematics
2 answers:
Semmy [17]2 years ago
5 0

∠1 and ∠8 are alternate exterior angles and ∠3 and ∠6 are alternate interior angles

step-by-step explanation:

When the transversal crosses line m and n, alternate angles are the pair of angles formed on the outside of each of the lines and opposite side of the transversal (∠1 and ∠8). However,alternate interior angles will form opposite of the transversal but inside the lines.(∠3 and ∠6 ).

Learn More

brainly.com/question/12441758

Keywords : Transversal, angles

#LearnwithBrainly

Bogdan [553]2 years ago
5 0

Answer:

a, b, e

Step-by-step explanation:

got it right on edge

You might be interested in
4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
2 years ago
A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year
uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that p = 0.8.

10 students, so n = 10

We have to find:

P(X \geq 9) = P(X = 9) + P(X = 10)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684

P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that p = 0.3758

Two groups, so n = 2

We have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0
2 years ago
Read 2 more answers
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho
abruzzese [7]

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (175) + 0.977* (175)

                                    = 787.5 + 170.975

                                    = 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (170) + 0.977* (170)

                                    = 765 + 166.09

                                    = 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

                                                                 = 958.475 - 931.09

                                                                 = 27.385 cm.

8 0
2 years ago
The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the w
Alex787 [66]
Hey there,

Your question states: <span>The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the width of the poster. What are the dimensions of the poster? </span>

l= 16 \ x  \ 1.25 = 20  in

Your correct answer would be \boxed{20}

Hope this helps.
4 0
2 years ago
Read 2 more answers
The manager at Jessica's Furniture Store is trying to figure out how much to charge for a couch that just arrived. The couch was
arlik [135]
Answer: $163.85

Explanation:

1) Data:

Purchase price: $ 113.00

mark up: 45%

2) Formula

selling price = purchase price + mark up

mark up = % * purchase price

3) Solution

mark up = 45% * $ 113.00 = 0.45 * $ 113.00 = $50.85

selling price = $ 113.00 + $ 50.85 = $ 163.85

Answer: $ 163.85
5 0
2 years ago
Read 2 more answers
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