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UkoKoshka [18]
2 years ago
10

Asa received scores of 72, 97, and 82 on her last three math tests. she needs a mean test score of 82 to qualify for the math te

am. what is the first step in determining how many points she needs on her next test to qualify for the team?
Mathematics
2 answers:
lara [203]2 years ago
6 0

First step is to find what should be the required total of sum of Score after fourth test, to identify how much more or less she need to score in his fourth test.

Since Mean = (Sum of Scores)/number of test

using above formula we determine what is the required sum of score.

82 = (Sum of Scores)/4

⇒ 82 × 4 = 328

So in four test she should have score total as 328

So Score require in fourth test = Required Score Total - (total score in 3 tests)

             = 328 - ( 72 + 97 + 82 ) = 77

So she need score of 77 to be at mean of 82 after fourth test and get qualify for the team


maria [59]2 years ago
4 0

Determine how many total points are needed to have an average of 82. Answer d

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Aubrey's dinner cost \$85$85dollar sign, 85. She tips the waitstaff 30\%30%30, percent for excellent service.
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<h3><u>Question:</u></h3>

Aubrey's dinner cost $85 . She tips the waitstaff 30% for excellent service. How much does Aubrey tip the waitstaff?

<h3><u>Answer:</u></h3>

Aubrey paid $ 25.5 to the wait staff

<h3><u>Solution:</u></h3>

Given that, Aubrey's dinner cost $ 85

She tips the waitstaff 30% for excellent service

We have to find the amount paid as tip to wait staff

Cost = $ 85

Tip = 30 %

So the tip amount paid is 30 % of 85

<h3><u>Find out 30 % of 85</u></h3>

Tip\ Amount = 30 \% \times 85\\\\Tip\ Amount = \frac{30}{100} \times 85\\\\Tip\ Amount = 0.30 \times 85\\\\Tip\ Amount = 25.5

Thus Aubrey paid $ 25.5 to waitstaff

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A bag has 10 marbles and 4 are black. Joseph picks 2 marbles without replacing the first. What is the probability that both are
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1 year ago
A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil
MArishka [77]

Answer:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

X \sim N(12,0.3)  

Where \mu=12 and \sigma=0.3

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}

If we solve for the total T we got:

T= n \bar X

For this case then the expected value and variance are given by:

E(T) = n E(\bar X) =n \mu

Var(T) = n^2 Var(\bar X)= n^2 \frac{\sigma^2}{n}= n \sigma^2

And the deviation is just:

Sd(T) = \sqrt{n} \sigma

So then the distribution for the total would be also normal and given by:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

And we want this probability:

P(T\leq 72)

And we can use the z score formula given by:

z = \frac{x-\mu}{\sigma}

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

6 0
2 years ago
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